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DaniilM [7]
3 years ago
13

Neo and the agent stand in different locations and the length of the line between them (their distance apart) is a measurement o

f _________.
A: space in one dimension
B: space in two dimensions
C: space in three dimensions
D: space in four dimensions
Physics
2 answers:
scZoUnD [109]3 years ago
5 0
I think their distance is a measurement of : B. space in two dimension

In two-dimensional space, both directions located in the same plane , and the distance in locations only separated by width and length (there is no volume in this model)
erastovalidia [21]3 years ago
3 0

Answer:

A. Space in one dimension

Explanation:

In Physics, we call dimension to the amount of numbers needed to determine the physical quantity we are measuring.

Thus, we need only one number to know what time is it (one-dimensional problem), but two numbers to know the coordinates of a point on earth's surface: latitude and longitude (two-dimensional problem).

In this case, we need only one number to know the distance between Neo and the Agent, which turns it a one-dimensional problem.

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Which equation would you use to solve the following problem? An object is moved 29 m with a force of 289 N. What is the work don
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How many hydrogen and carbon atoms in a diamond
Wewaii [24]

Answer:

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4 0
3 years ago
An initially stationary object experiences an acceleration of 6 m/s2 for a time of 15 s. How far will it travel during that time
andrew-mc [135]

Answer:

The object will travel 675 m during that time.

Explanation:

A body moves with constant acceleration motion or uniformly accelerated rectilinear motion (u.a.r.m) when the path is a straight line, but the velocity is not necessarily constant because there is an acceleration.

In other words, a body performs a u.a.r.m when its path is a straight line and its acceleration is constant. This implies that the speed increases or decreases uniformly.

In this case, the position is calculated using the expression:

x = xo + vo*t + ½*a*t²

where:

  • x0 is the initial position.
  • v0 is the initial velocity.
  • a is the acceleration.
  • t is the time interval in which the motion is studied.

In this case:

  • x0= 0
  • v0= 0  because the object is initially stationary
  • a= 6 \frac{m}{s^{2} }
  • t= 15 s

Replacing:

x= 0 + 0*15 s + ½*6 \frac{m}{s^{2} }*(15s)²

Solving:

x=½*6 \frac{m}{s^{2} }*(15s)²

x=½*6 \frac{m}{s^{2} }*225 s²

x= 675 m

<u><em> The object will travel 675 m during that time.</em></u>

5 0
2 years ago
According to the barometer in the attachment below, which statement is true?
mixer [17]

Your answer is A

Pls mark me brainiest and I sure hope this helps you

8 0
2 years ago
Read 2 more answers
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