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DaniilM [7]
3 years ago
13

Neo and the agent stand in different locations and the length of the line between them (their distance apart) is a measurement o

f _________.
A: space in one dimension
B: space in two dimensions
C: space in three dimensions
D: space in four dimensions
Physics
2 answers:
scZoUnD [109]3 years ago
5 0
I think their distance is a measurement of : B. space in two dimension

In two-dimensional space, both directions located in the same plane , and the distance in locations only separated by width and length (there is no volume in this model)
erastovalidia [21]3 years ago
3 0

Answer:

A. Space in one dimension

Explanation:

In Physics, we call dimension to the amount of numbers needed to determine the physical quantity we are measuring.

Thus, we need only one number to know what time is it (one-dimensional problem), but two numbers to know the coordinates of a point on earth's surface: latitude and longitude (two-dimensional problem).

In this case, we need only one number to know the distance between Neo and the Agent, which turns it a one-dimensional problem.

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An ice cube of mass 50.0 g can slide without friction up and down a 25.0 degree slope. The ice cube is pressed against a spring
lozanna [386]

Answer:

0.6 m

Explanation:

When a spring is compressed it stores potential energy. This energy is:

Ep = 1/2 * k * x^2

Being x the distance it compressed/stretched.

When the spring bounces the ice cube back it will transfer that energy to the cube, it will raise up the slope, reaching a high point where it will have a speed of zero and a potential energy equal to what the spring gave it.

The potential energy of the ice cube is:

Ep = m * g * h

This is vertical height and is related to the distance up the slope by:

sin(a) = h/d

h = sin(a) * d

Replacing:

Ep = m * g * sin(a) * d

Equating both potential energies:

1/2 * k * x^2 = m * g * sin(a) * d

d = (1/2 * k * x^2) / (m * g * sin(a))

d= (1/2 * 25 * 0.1^2) / (0.05 * 9.81 * sin(25)) = 0.6 m

8 0
3 years ago
Please help answer question​
nika2105 [10]

Answer:

C = 1.01

Explanation:

Given that,

Mass, m = 75 kg

The terminal velocity of the mass, v_t=60\ m/s

Area of cross section, A=0.33\ m^2

We need to find the drag coefficient. At terminal velocity, the weight is balanced by the drag on the object. So,

R = W

or

\dfrac{1}{2}\rho CAv_t^2=mg

Where

\rho is the density of air = 1.225 kg/m³

C is drag coefficient

So,

C=\dfrac{2mg}{\rho Av_t^2}\\\\C=\dfrac{2\times 75\times 9.8}{1.225\times 0.33\times (60)^2}\\\\C=1.01

So, the drag coefficient is 1.01.

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3 years ago
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F. Diagram C & D
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<em>Answer:</em>

<em> </em>

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