A truck covers 40.0 m in 7.10 s while smoothly slowing down to a final velocity of 2.75 m/s.. (a) Find the truck's original spee
1 answer:
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Answer:
<em>63.44 rad/s</em>
<em></em>
Explanation:
mass of bullet = 3.3 g = 0.0033 kg
initial velocity of bullet = 250 m/s
final velocity of bullet = 140 m/s
loss of kinetic energy of the bullet =
==> = 70.785 J
this energy is given to the stick
The stick has mass = 250 g =0.25 kg
its kinetic energy = 70.785 J
from
KE =
70.785 =
566.28 =
= 23.79 m/s
the stick is 1.5 m long
this energy is impacted midway between the pivot and one end of the stick, which leaves it with a radius of 1.5/4 = 0.375 m
The angular speed will be
Ω = v/r = 23.79/0.375 =<em> 63.44 rad/s</em>
Answer:
Look to the explanation
Explanation:
<u><em>Work done</em></u> is is the energy transferred to or from an object by means
of a force acting on the object.
Work is positive if energy transferred to the object, and work is
negative if energy transferred from the object.
<em>Work = Force in the direction motion of object × its displacement</em>
The SI unit of the work is joule (J)
<u><em>Power</em></u> is the rate of work
<em>Power = work done ÷ time taken</em>
Power =
Displacement (s) ÷ time (t) = velocity (v)
<em>Power = Force × velocity</em>
The SI unit of the power is watt (w)