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3 years ago

12

Which of the following is known as the pulse of a wave?

1 answer:

MrMuchimi3 years ago

4 0

Which of the following is known as the pulse of a wave?

A non-recurrent wave and one cycle of a wave motion.

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Compare the forces in a small nucleus to the forces in a large nucleus

pochemuha

The comparison of the forces in a small nucleus to the forces of a large one is the fact that they are capable of holding the protons and neutrons which made it no matter what their size may be. Therefore, as long as there is a nucleus, their forces can both hold together the two atoms tight.

6 0

3 years ago

A ladybug sits 10.8 cm from the center of a beatles music album spinning at 33.33 rpm. What is the maximum velocity (in m/s) of

snow_lady [41]

Answer:

The maximum velocity is 0.377 m/s

Explanation:

Please, the solution is in the Word file attached

7 0

3 years ago

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Sodium hydroxide (NaOH) was added to pure water (H2O). Which most likely were the pH values of the water before and after the so

Anastaziya [24]

Before 7 after 9. A pH smaller than 7 indicates acidity with 0 being completely acidic. A pH greater than 7 shows alkalinity with 14 being completely alkaline. 7 is neutral. Since NaOH is alkaline, adding it to a neutral substance would increase the pH and it would increase from 7 to 9.

3 0

3 years ago

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when a constant force acts upon an object the acceleration of the object varies inversely with its mass. when a certain constant

solong [7]

Explanation:

When a constant force acts upon an object the acceleration of the object varies inversely with its mass.

$a\propto \dfrac{1}{m}$

or

$\dfrac{a_1}{a_2}=\dfrac{m_2}{m_1}$

If m₁ = 21 kg, a₁ = 3 m/s², m₂ = 9 kg

We need to find a₂

So,

$a_2=\dfrac{m_1a_1}{m_2}\\\\a_2=\dfrac{21\times 3}{9}\\\\a_2=7\ m/s^2$

So, if mass is 9 kg, its acceleration is 7 m/s².

8 0

2 years ago

A charged particle accelerated to a velocity v enters the chamber of a mass spectrometer. The particle's velocity is perpendicul

gladu [14]

Answer:

Circle

Explanation:

When a charged particle is in motion in a region with magnetic field, the particle experiences a force whose magnitude is given by

$F=qvB sin \theta$

where

q is the charge

v is the velocity of the particle

B is the strength of the magnetic field

$\theta$ is the angle between the directions of v and B

In this problem, the velocity of the particle is perpendicular to the magnetic field, so

$\theta=90^{\circ}$

and the formula reduces to

$F=qvB$

Also, the direction of this force is perpendicular to the direction of motion of the particle. This means that as the charge moves in the region of the magnetic field, the force acting on it acts as a centripetal force: therefore, the particle will start moving by unifom circular motion, with constant speed (because the magnetic force does no work on the particle, since it is perpendicular to the direction of motion).

So, the path of the particle will be a circle.

4 0

3 years ago