Given -
50 times 4 =200
Find out the values of 500 times 400.
To prove
As given in the question
50 times 4 =200
i.e the above also written in the form as follows.
50 × 4 = 200
Now find out for 500 times 400.
500 times 400 is also written in the form as follows .
500 × 400 = 200000
Therefore the 500 times 400 is 200000.
Hence proved
They are both in the thousands places
QUESTION 1
Let the numbers be x and y.
It was given that the numbers are in the ratio 5:2.
This implies that,
The sum of the numbers is
The difference is
The ratio if the sum to the difference is
QUESTION 2
Let the numbers be m and n.
This implies that,
Also,
We rewrite this as a fraction to get,
We make m the subject to get,
We put equation (2) into equation (1) to get,
The numbers are 42 and 49.
The answers the problem is 2+2=4
If ray EB bisects angle AEC, then m∠AEB=m∠BEC=4x+1.
Angles AEB, BEC and CED together form right angle AED, then
m∠AEB+m∠BEC+m∠CED=90°.
Therefore,
(4x+1)+(4x+1)+3x=90,
11x=90-2,
11x=88,
x=88:11,
x=8°.
Then m∠BEC=4x+1=4·8+1=33°.
Answer: x=8°, m∠BEC=33°.