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mr Goodwill [35]
3 years ago
10

QUICK BEING TIMED

Mathematics
2 answers:
Snezhnost [94]3 years ago
8 0

Answer:18

Step-by-step explanation:

Finger [1]3 years ago
6 0

Answer:

18 inches

Step-by-step explanation:

If 25 miles = 2 inches on a map, then 225 miles is 18 inches. Divide 225 by 25, and you get 9. Then multiply by 2 and get 18. The answer is 18. Hope this helps.

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For this you are subtrating polynomial expressions
slava [35]
Hi, The answer is 2x^2-8x+12, because when you subtract the polynomial with the answer you will get x^2-4
3 0
2 years ago
What is 41 divided by 3605
gladu [14]
87.9 is about the answer
4 0
3 years ago
Read 2 more answers
-1+8v=2+8v what is the value of v?
Nesterboy [21]

Answer: There are no solutions.

Step-by-step explanation:

6 0
2 years ago
mercury orbits the sun in 87 and 24/50 venus orbits the sun in 224 and 7/10 earthdays and mars orbits the sun in 686 and 49/50 d
slega [8]
Mercury: 87 24/25
Venus 224 7/10
Mars 686 49/50

All we need to do is to convert fractions so they have a denominator of 10, 100, 1000 etc.

87 24/25 = 87 96/100
224 7/10 stays the same
686 49/50 = 686 98/100

Now we can easily convert them into decimals:

Mercury: 87.96
Venus: 224.7
<span>Mars: 686.98</span>
7 0
2 years ago
Suppose that $3000 is placed in an account that pays 16% interest compounded each year. Assume that no withdrawals are made from
Papessa [141]

Answer:

a) $3480

b) $4036.8

Step-by-step explanation:

The compound interest formula is given by:

A(t) = P(1 + \frac{r}{n})^{nt}

Where A(t) is the amount of money after t years, P is the principal(the initial sum of money), r is the interest rate(as a decimal value), n is the number of times that interest is compounded per year and t is the time in years for which the money is invested or borrowed.

Suppose that $3000 is placed in an account that pays 16% interest compounded each year.

This means, respectively, that P = 3000, r = 0.16, n = 1

So

A(t) = P(1 + \frac{r}{n})^{nt}

A(t) = 3000(1 + \frac{0.16}{1})^{t}

A(t) = 3000(1.16)^{t}

(a) Find the amount in the account at the end of 1 year.

This is A(1).

A(t) = 3000(1.16)^{t}

A(1) = 3000(1.16)^{1} = 3480

(b) Find the amount in the account at the end of 2 years.

This is A(2).

A(2) = 3000(1.16)^{2} = 4036.8

4 0
3 years ago
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