Step-by-step explanation:
Conversion a mixed number 5 3/2
to an improper fraction: 5 3/2 = 5 3/2
= 5 · 2 + 3/2
= 10 + 3/2
= 13/2
To find a new numerator:
a) Multiply the whole number 5 by the denominator 2. Whole number 5 equally 5 * 2/2
= 10/2
b) Add the answer from previous step 10 to the numerator 3. New numerator is 10 + 3 = 13
c) Write a previous answer (new numerator 13) over the denominator 2.
Five and three halfs is thirteen halfs
Conversion a mixed number 3 6/7
to an improper fraction: 3 6/7 = 3 6/7
improper fraction: 3 6/7 = 3 6/7
3 · 7 + 6/7 = 21 + 6/7 =27/7
To find a new numerator:
a) Multiply the whole number 3 by the denominator 7. Whole number 3 equally 3 * 7/7
= 21/7
b) Add the answer from previous step 21 to the numerator 6. New numerator is 21 + 6 = 27
c) Write a previous answer (new numerator 27) over the denominator 7.
Three and six sevenths is twenty-seven sevenths
Multiple:
13/2 * 27/7 = 13/2 · 27/7 = 351/14
Answer:
Step-by-step explanation:
Question
What is the value of x?
12 units
Answer:
Step-by-step explanation:18
15 units
20 units
24 units
Answer:
Step-by-step explanation:
Given that the demand for the 6 p.m. flight from Toledo Express Airport to Chicago's O'Hare Airport on Cheapfare Airlines is normally distributed with a mean of 132 passengers and a standard deviation of 42
Let X be the no of passengers who report
X is N(132, 42)
Or Z is 
a) Suppose a Boeing 757 with a capacity of 183 passengers is assigned to this flight.
the probability that the demand will exceed the capacity of this airplane
=
b) the probability that the demand for this flight will be at least 80 passengers but no more than 200 passengers
=
=0.4474+0.3907
=0.8381
c) the probability that the demand for this flight will be less than 100 passengers
d) If Cheapfare Airlines wants to limit the probability that this flight is overbooked to 3%, how much capacity should the airplane that is used for this flight have? passengers
=
e) 79th percentile of this distribution
=
Answer:
522
Step-by-step explanation:
#11
Each roll is 9' long,
length of each roll = 9' * (12"/foot) = 108"
Each ribbon piece = 15", so number of ribbons per roll
=108/15=7 with 3" left over, which is assumed not possible to be joined with other pieces.
Therefore, with 5 rolls, there are 7*5=35 pieces of ribbon, with 5 pieces or 3" left over.
