The equation of the hyperbola with directrices at x = ±2 and foci at (5, 0) and (−5, 0) is 
<h3>How to determine the equation of the hyperbola?</h3>
The given parameters are:
- Directrices at x = ±2
- Foci at (5, 0) and (−5, 0)
The foci of a hyperbola are represented as:
Foci = (k ± c, h)
The center is:
Center = (h,k)
And the directrix is:
Directrix, x = h ± a²/c
By comparison, we have:
k ± c = ±5
h = 0
h ± a²/c = ±2
Substitute h = 0 in h ± a²/c = ±2
0 ± a²/c = ±2
This gives
a²/c = 2
Multiply both sides by c
a² = 2c
k ± c = ±5 means that:
k ± c = 0 ± 5
By comparison, we have:
k = 0 and c = 5
Substitute c = 5 in a² = 2c
a² = 2 * 5
a² = 10
Next, we calculate b using:
b² = c² - a²
This gives
b² = 5² - 10
Evaluate
b² = 15
The hyperbola is represented as:

So, we have:

Evaluate

Hence, the equation of the hyperbola is 
Read more about hyperbola at:
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Answer:
24 units
Step-by-step explanation:
Look at the coordinate plane. First start with the bottom side (LN). The line goes from -3 to 9. This means that the line is 12 units long. Now, look at the other sides. MN goes from 3 to 9, therefore, the line is 6 units long. Lastly, look at ML— -3 to 3, therefore, the line is 6 units long. Add them all up, (12+6+6) and it equals 24 units.
Answer:
I don't think you are doing anything wrong. Just ignore it and write the repeating decimal. If you're asked to do it, round it up instead.
V=(1/3)hpir^2
v=130
h=13
r=x
130=(1/3)(13)pix^2
times both sides by 3
390=13pix^2
divide both sides by 13
30=pix^2
divide both sides by pi
30/pi=x^2
sqrt both sides
x≈3.09
radius is abou 3 units