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Lina20 [59]
3 years ago
13

Can someone help me? I don't know the answer and I need a justification for why the correct answer is correct

Chemistry
1 answer:
pav-90 [236]3 years ago
7 0

Answer:

(A) The value of Kc for this reaction increases as temperature increases, because the reaction is endothermic.

Step-by-step explanation:

   N₂O₄      ⇌       2NO₂

colourless      reddish-brown

NO₂ is a reddish-brown gas, while N₂O₄ is colourless.

When you cooled the sample to 0 °C, the position of equilibrium shifted to form more N₂O₄, that is, it <em>shifted to the left</em>.

According to <em>Le Châtelier's Principle,</em> when a stress is applied to a system at equilibrium, the system will respond in a way that tends to relieve the stress.

You applied a stress: you removed heat from the system. It responded by shifting in the direction that produces more heat (<em>to the left</em>).

If you consider heat as part of the reaction, the equation must be

N₂O₄ + heat ⇌ 2NO₂

The reaction is endothermic.

Furthermore, since the position of equilibrium shifted in the direction of reactants, the equilibrium constant decreased.

The value of K <em>decreases as the temperature decreases</em>. If we say it the other way, the value of K increases as the temperature increases.

The correct answer is (A) The value of Kc for this reaction increases as temperature increases, because the reaction is endothermic.

(B) and (D) are <em>wrong</em>, because the reaction is endothermic.

(C) is <em>wrong</em>, because the value of Kc decreases as temperature decreases.

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