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3 years ago

Can someone help me? I don't know the answer and I need a justification for why the correct answer is correct

Chemistry

1 answer:

pav-90 [236]3 years ago

7 0

Answer:

(A) The value of Kc for this reaction increases as temperature increases, because the reaction is endothermic.

Step-by-step explanation:

N₂O₄ ⇌ 2NO₂

colourless reddish-brown

NO₂ is a reddish-brown gas, while N₂O₄ is colourless.

When you cooled the sample to 0 °C, the position of equilibrium shifted to form more N₂O₄, that is, it shifted to the left.

According to Le Châtelier's Principle, when a stress is applied to a system at equilibrium, the system will respond in a way that tends to relieve the stress.

You applied a stress: you removed heat from the system. It responded by shifting in the direction that produces more heat (to the left).

If you consider heat as part of the reaction, the equation must be

N₂O₄ + heat ⇌ 2NO₂

The reaction is endothermic.

Furthermore, since the position of equilibrium shifted in the direction of reactants, the equilibrium constant decreased.

The value of K decreases as the temperature decreases. If we say it the other way, the value of K increases as the temperature increases.

The correct answer is (A) The value of Kc for this reaction increases as temperature increases, because the reaction is endothermic.

(B) and (D) are wrong, because the reaction is endothermic.

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Explain how the following experimental errors affect the final calculation of the kilocalories per gram for a food item. Be spec

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Answer:

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Explanation:

a) the final kilocalories per gram for food will be less because the mass was reduced from 110.3 to 101.3g

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3 years ago

For the following reaction, 38.3 grams of sulfuric acid are allowed to react with 33.5 grams of calcium hydroxide sulfuric acid(

Likurg_2 [28]

Answer:

What is the maximum amount of calcium sulfate that can be formed? 53.1 grams CaSO4

What is the FORMULA for the limiting reagent? H2SO4

What amount of the excess reagent remains after the reaction is complete? 4.59 grams of Ca(OH)2

Explanation:

Step 1: Data given

Mass of sulfuric acid = 38.3 grams

Molar mass of H2SO4 = 98.08 g/mol

Mass of calcium hydroxide = 33.5 grams

Molar mass of Ca(OH)2 = 74.09 g/mol

Step 2: The balanced equation

H2SO4 + Ca(OH)2 → CaSO4 + 2H2O

Step 3: Calculate moles of H2SO4

moles H2SO4 = mass H2SO4 / molar mass H2SO4

moles H2SO4 = 38.3 grams / 98.08 g/mol

moles H2SO4 = 0.390 moles

Step 4: Calculate moles of Ca(OH)2

moles Ca(OH)2 = 33.5 grams / 74.09 g/mol

moles Ca(OH)2 =0.452 moles

Step 5: Calculate limiting reactant

For 1 mol H2SO4, we need 1 mol of Ca(OH)2 to produce, 1 mol of CaSO4 and 2 mol of H2O

H2SO4 is the limiting reactant. It will completely be consumed (0.390 moles).

Ca(OH)2 is in excess. There will be consumed 0.390 moles

There will remain 0.452 - 0.390 = 0.062 moles

This is 0.062 * 74.09 g/mol = 4.59 grams

Step 6: Calculate moles of calcium sulfate

For 1 mol H2SO4, we need 1 mol of Ca(OH)2 to produce, 1 mol of CaSO4 and 2 mol of H2O

For 0.390 moles of H2SO4, there will be produced 0.390 moles of CaSO4

Step 7: Calculate mass of CaSO4

Mass CaSO4 = moles CaSO4 * molar mass CaSO4

Mass CaSO4 = 0.390 moles * 136.14 g/mol

Mass of CaSO4 = 53.1 grams

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3 years ago

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Answer:

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3 years ago

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