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zhannawk [14.2K]
2 years ago
11

Pls help ty so much!

Chemistry
1 answer:
Nitella [24]2 years ago
4 0

\quad \huge \quad \quad \boxed{ \tt \:Answer }

\qquad \tt \rightarrow \:mass = 11.42 \:\: grams

____________________________________

\large \tt Solution  \: :

\qquad \tt \rightarrow \: Q = ms\Delta T

  • \textsf{Q = heat evolved/absorbed = 501 J}

  • \textsf{m = mass in gram = ?}

  • \textsf{s = specific heat = 0.45}

  • \textsf{ΔT = change in temp = 120 - 22.5 =97.5°C}

\large\textsf{Find m : }

\qquad \tt \rightarrow \: 501 = m \sdot(0.45) \sdot(97.5)

\qquad \tt \rightarrow \:  501 = m \sdot43.875

\qquad \tt \rightarrow \: m =  \dfrac{501}{43.875}

\qquad \tt \rightarrow \: m  \approx11.42 \:  \: g

Answered by : ❝ AǫᴜᴀWɪᴢ ❞

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Predict the geometry around the central atom in SO2- A) trigonal pyramidal B) tetrahedral C) octahedral D) trigonal planar E) tr
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<u>Answer:</u> The correct answer is Option D.

<u>Explanation:</u>

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where,

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N = number of monovalent atoms bonded to central atom  = 0

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Th e molar absorption coeffi cient of a substance dissolved in water is known to be 855 dm3 mol−1 cm−1 at 270 nm. To determine t
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Answer : The percentage reduction in intensity is 79.80 %

Explanation :

Using Beer-Lambert's law :

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\log \frac{I_o}{I}=\epsilon \times C\times l

where,

A = absorbance of solution

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Now put all the given values in the above formula, we get:

\log \frac{I_o}{I}=(855dm^3mol^{-1}cm^{-1})\times (3.25\times 10^{-3}mol.dm^{-3})\times (0.25cm)

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