What is normality and molarity of the concentration of solution?

Chemistry

2 answers:

nordsb [41]3 years ago

7 0

Answer:

<u>Molarity and normality describe the numbers (moles) of reactants or products dissolved in one liter of solution.</u> Molarity: M = moles of solute contained in one liter of solution. ... <u>Normality is always a multiple of molarity. It describes the “equivalent” moles of reactants involved in chemical reactions.</u>

Explanation:

Normality is a measure of concentration equal to the gram equivalent weight per litre of solution. Gram equivalent weight is the measure of the reactive capacity of a molecule. The solute's role in the reaction determines the solution's normality. Normality is also known as the equivalent concentration of a solution.

Molar concentration is a measure of the concentration of a chemical species, in particular of a solute in a solution, in terms of amount of substance per unit volume of solution.

Formula for Molar: M = $\frac{n}{v}$

svlad2 [7]3 years ago

4 0

Answer:

Normality is the number of gram equivalents of solute divided by the volume in liters.

The molarity is the amount of moles in solute divided by the volume in liters.

Moles are the molar mass times grams if you're curious

I hope this helps and good luck!

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A gas has a pressure of 8.5atm and occupies 24L at 25∘C. What volume (in liters) will the gas occupy if the pressure is increase

Vesna [10]

The volume (in liters) that the gas will occupy if the pressure is increased to 13.5 atm and the temperature is decreased to 15 °C is 15 L

From the question given above, the following data were obtained:

Initial pressure (P₁) = 8.5 atm

Initial volume (V₁) = 24 L

Initial temperature (T₁) = 25 °C = 25 + 273 = 298 K

Final pressure (P₂) = 13.5 atm

Final temperature (T₂) = 15 °C = 15 + 273 = 288 K

<h3>Final volume (V₂) =? </h3>

The final volume of the gas can be obtained by using the combined gas equation as illustrated below:

$\frac{P_{1}V_{1}}{T_{1}} = \frac{P_{2}V_{2}}{T_{2}}\\\\\frac{8.5 * 24}{298} = \frac{13.5 * V_{2}}{288}\\\\ \frac{204}{298} = \frac{13.5 * V_{2}}{288}\\\\$