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2 years ago

What are some compounds that are made from the element copper?

Chemistry

1 answer:

PSYCHO15rus [73]2 years ago

6 0

Answer:

All of these compounds are made from the element copper. Copper Acetates, Cuprous Oxide, Cupric Oxide (otherwise know as black copper oxide), Cupric Chloride, Copper Oxychloride, Cuprous Chloride, Cupric Nitrate, Copper Cyanide.

Explanation:

Copper is considered an element. You can use copper for Jewelry, Table Tops, Sinks, Dark Chocolate, Leafy Greens, Lobster, Nuts and Seeds, Mushrooms, Oysters, Liver and etc other nutrience. Copper is an easily molded base metal that is often added to precious metals to improve their elasticity, flexibility, hardness, colour, and resistance to corrosion.

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Irina-Kira [14]

Answer:

Sound energy is what we get from an MP3 player

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Explanation:

4 0

3 years ago

175.24g of strontium equals how many moles

OverLord2011 [107]

Using dimensional analysis, we can find the moles of strontium by comparing the mass of strontium to it's atomic mass.
You can find the atomic mass of Sr on the periodic table:
Atomic Mass Sr = 87.62g/mol

In case you are not familiar, dimensional analysis works like this:
(what we know) x (conversion factor) = what we are looking for

The conversion factor compares the units of what we know to the units of what we are looking for. In this case, the conversion factor is:
1 mol/87.62g

The important thing to note about the conversion factor is that you want to be able to cancel out the units of your given measurement (in this case, it is the mass)

So, our full solution will be:
moles Sr = (175.24 g)x(1 mol/87.62 g)
(cancel out the mass units)
moles Sr = 175.24 x 1 mol/87.62
= 2.00 mol Sr

Hope this helped you!

4 0

3 years ago

If a solution containing 45.101 g of mercury(II) acetate is allowed to react completely with a solution containing 12.026 g of s

AnnyKZ [126]

Answer:

14.533 grams of solid precipitate of mercury(II) dichromate will form.

Explanation:

$Hg(CH_3COO)_2(aq)+Na_2Cr_2O_7(aq)\rightarrow HgCr_2O_7(s)+2CH_3COONa(aq)$

Moles of mercury(II) acetate = $\frac{45.101 g}{318.70 g/mol}=0.14152 mol$

Moles of sodium dichromate = $\frac{12.026 g}{261.97 g/mol}=0.045906 mol$

According to reaction , 1 mole of sodium dichromate reacts with 1 mole of mercury(II) acetate , then 0.045906 moles of sodium dichromate will recat with :

$\frac{1}{1}\times 0.045906 mol=0.045906 mol$ of mercury(II) acetate

This means that mercury(II) acetate is present in an excess amount and sodium dichromate is present in limiting amount.So, amount of precipitate will depend upon moles of sodium dichromate.

According to reaction , 1 mole of sodium dichromate gives 1 mole of mercury(II) dichromate , then 0.045906 moles of sodium dichromate will give :

$\frac{1}{1}\times 0.045906 mol=0.045906 mol$ of mercury(II) dichromate

Mass of 0.045906 moles of mercury(II) dichromate:

0.045906 mol × 316.59 g/mol = 14.533 g

14.533 grams of solid precipitate of mercury(II) dichromate will form.

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3 years ago

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