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LUCKY_DIMON [66]
4 years ago
7

Determine the minimum applied force p required to move wedge a to the right. the spring is compressed a distance of 185 mm. negl

ect the weight of a and
b. the coefficient of static friction for all contacting surfaces is μs=0.35. neglect friction at the rollers.
Physics
1 answer:
Pie4 years ago
7 0

By equation of equilibrium and friction:

Fb = Kx = 15(0.175) = 2.625 kN.

The wedge is on the verge of moving right then slipping will have to occur at both contact surfaces.

Fa = usNa = 0.35Na

Fb = 0.35Nb

Nb = 2.625 = 0; Nb = 2.625 kN

Nacos10 – 0.35Na sin 10 = 2.625 = 0

Na = 2.841 kN

P – (0.35 * 2.625) – 0.35 (2.841) cos 10 – 2.841 sin 10 = 0

P = 2.39 kN

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A meteorologist plans to release a weather balloon from ground level, to be used for high-altitude atmospheric measurements. The
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Answer:

563.86 N

Explanation:

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F = ρgV where ρ = density of air = 1.29 kg/m³, g = acceleration due to gravity = 9.8 m/s² and V = volume of balloon = 4πr/3 (since it is a sphere) where r = radius of balloon = 2.20 m

So, F = ρgV = ρg4πr³/3

substituting the values of the variables into the equation, we have

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3 years ago
Astrology is considered a science because it is grounded in scientific research. Please select the best answer from the choices
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Answer:

False. Astrology is not a science.

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7 0
4 years ago
(b) A cylinder of cross-sectional area 0.65m2 and
VLD [36.1K]

Answer:

The volume of the cavity is 0.013m^3

Explanation:

To find the volume of the cavity, the major parameter missing is the diameter of the cavity itself. we can obtain this using the following steps:

Step one:

Obtain the volume of the cylinder by dividing the mass of the cylinder by the density.

Volume of the cylinder = 2.1 / 11.053 =0.19m^{3}

Step two:

From the volume of the cylinder, we can get the radius of the cylinder.

radius = \sqrt{\frac{V}{\pi \times h}}  = \sqrt{\frac{0.19}{\pi \times 0.32}} =0.44m

Step three:

From the cross-sectional area, we can obtain the radius of the cavity.

Let the radius of the cavity be = r, while the radius of the cylinder be = R

CSA of cavity =

\pi({R^2}-r^2) = CSA\\0.65 = \pi (0.32^2-r^2)\\r= 0.115m

Step Four:

calculate the volume of the cavity using volume =\pi r^2 \times h

Recall that the cavity has the same height as the original cylinder

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8 0
3 years ago
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