I believe this question has the following sub questions:
1. When the climber ascends the mountain before
acclimating, ___ to restore homeostasis within the body. <span>
2. As the climber rehydrates and rests at a
basecamp, hemoglobin (Hb) is produced, which is the body's response to the
stress. As a result, ___ </span>
3. When the climber returns to sea level before
reacclimating, ___ to restore homeostasis within the body.
4. As the climber reacclimates to sea level,
hemoglobin is replaced at a lower rate, decreasing hemoglobin concentrations in
the blood. As a result, ___
The answers on each sub question are:
1) Equilibrium shifts to release O2<span>
<span>2) Equilibrium shifts to formation of HbO2</span>
<span>3) Equilibrium shifts to formation of HbO2</span>
<span>4) Equilibrium shifts to release O2</span></span>
North and south will apply
Answer:
150000000

49050000 N/C
Explanation:
q = Charge = 24 pC
m = Mass of honeybee = 0.12 g
E = Electric field = 100 N/C
g = Acceleration due to gravity = 9.81 m/s²

Number electrons is

The number of electrons added or removed was 150000000
Force is given by

The ratio is

The ratio is 
Balancing the forces we get

The electric field required is 49050000 N/C