Calculate the magnitude of the gravitational force exerted by the Moon on a 79 kg human standing on the surface of the Moon. (Th
1 answer:
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Explanation:
Given that,
Wavelength of the photon,
Work function of the metal,
We need to find the maximum kinetic energy of the ejected electrons. It can be calculated using Einstein's photoelectric equation as :
or
So, the maximum kinetic energy of the ejected electrons is 3 ev. Hence, this is the required solution.
Answer:
so the transverse displacement is 0.089963 m
Explanation:
Given data
equation y(x,t)=Acos(kx−ωt)
speed v = 9.00 m/s
amplitude A = 9.00 × 10^−2 m
wavelength λ = 0.480 m
to find out
the transverse displacement
solution
we know
v = angular frequency / wave number
and
wave number = 2 / λ = 2
/ 0.480 = 13.0899
angular frequency = v k
angular frequency = 9.00 × 13.0899
angular frequency = 117.8097 rad/sec = 118 rad/sec
so
equation y(x,t)=Acos(kx−ωt)
y(x,t)=9.00 × 10^−2 cos(13.0899 x−118t)
when x =0 and and t = 0
maximum y(x,t)= 9.00 × 10^−2 cos(13.0899 (0) − 118 (0))
maximum y(x,t)= 9.00 × 10^−2 m
and when x = x = 1.59 m and t = 0.150 s
y(x,t)=9.00 × 10^−2 cos(13.0899 (1.59) −118(0.150) )
y(x,t)=9.00 × 10^−2 × (0.99959)
y(x,t) = 0.089963 m
so the transverse displacement is 0.089963 m