Tetrahedral arrangement is resulted upon mixing one s and three p atomic orbitals, resulting in 4 hybridized
orbitals →
hybridization.
<h3>What is
orbital hybridization?</h3>
In the context of valence bond theory, orbital hybridization (or hybridisation) refers to the idea of combining atomic orbitals to create new hybrid orbitals (with energies, forms, etc., distinct from the component atomic orbitals) suited for the pairing of electrons to form chemical bonds.
For instance, the valence-shell s orbital joins with three valence-shell p orbitals to generate four equivalent sp3 mixes that are arranged in a tetrahedral configuration around the carbon atom to connect to four distinct atoms.
Hybrid orbitals are symmetrically arranged in space and are helpful in the explanation of molecular geometry and atomic bonding characteristics. Usually, atomic orbitals with similar energies are combined to form hybrid orbitals.
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Answer:
Antigens are molecules capable of stimulating an immune response. Each antigen has distinct surface features, or epitopes, resulting in specific responses. Antibodies (immunoglobins) are Y-shaped proteins produced by B cells of the immune system in response to exposure to antigens.
Answer:
H2SO4 + CO3 = H2CO3 + SO4
Explanation:
H2SO4 + CO3
This is the reaction of sulphuric acid and carbon trioxide.
Balanced reaction is;
H2SO4 + CO3 = H2CO3 + SO4
So they react to produce carbonic acid and sulfate.
Answer:
91.2 nm
Explanation:
The Rydberg equation is given by the formula
1/ λ = Rh ( 1/ n₁² - 1/ n₂²)
where
λ is the wavelength
Rh is Rydberg constant
and n₁ and n₂ are the energy levels of the transion.
We can see from this equation that the wavelength is inversely proportional to the difference of the squares of the inverse of the quantum numbers n₁ and n₂. It follows then that the smallest wavelength will be given when the the transitions are between the greatest separation between n₁ and n₂ whicg occurs when n1= 1 and n₂= ∞ , that is the greater the separation in energy levels the shorter the wavelength.
Substituting for n₁ and n₂ and solving for λ :
1/λ = 1.0974 x 10⁷ m⁻¹ x ( 1/1² -1/ ∞²) = 1.0974 x 10⁷ m⁻¹ x ( 1/1² - 0) =
λ = 1/1.0974 x 10⁷ m = 9.1 x 10⁻8 m = 91.2 nm
Answer:
Basic solution
Explanation:
A solution containing 0.005 M potassium hydroxide has a pH of;
pOH= -log[0.005]
pOH= 2.3
But pH+pOH=14
Therefore;
pH= 14-pOH
Hence;
pH= 14-2.3= 11.7
A solution having a pH of 11.3 is clearly a basic solution because this pH indicates a substance that is basic in nature. Hence the answer given.