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Vlada [557]
3 years ago
6

Max Plank created the idea of quanta4 or quantum energy. This is?

Chemistry
1 answer:
Margaret [11]3 years ago
6 0

Answer:

A theory of physics in which energy exists only in discrete quantities, called quanta. It was originated in 1900 by the German physicist Max Karl Ernst Ludwig Planck (1858–1947), who suggested that electromagnetic radiation is quantized, i.e. it can be emitted or absorbed only in tiny packets, not continuously.

Explanation:

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How many moles of AlCl3 are formed by 1.53 moles of CuCl2?
jolli1 [7]

Answer:

1.02 moles of AlCl3

Explanation:

Consider the balanced reaction equation shown below;

2Al(s) + 3CuCl2(aq) -------> 2AlCl3 (aq) + 3Cu(s)

This is the balanced reaction equation for the reaction going on above. Recall that the first step in solving any problem is to accurately put down the chemical reaction equation. This balanced reaction equation always serves a reliable guide in solving the problem at hand.

Given that;

3 moles of CuCl2 yields 2 moles of AlCl3

1.53 moles of CuCl2 yields 1.53 × 2 / 3 =1.02 moles of AlCl3

5 0
2 years ago
How many hydrogen atoms are in water, H2O?<br><br> A) 1<br> B) 2<br> C) 3<br> D) 0
pishuonlain [190]
There are two hydrogen atoms in one molecule of water.

The answer is B) 2
8 0
2 years ago
Read 2 more answers
7. If all of the forces on an object are balanced, the object?
dolphi86 [110]

Answer:

Is balanced

Explanation:

4 0
3 years ago
1. What is the potential energy of a 8 kg ball that is at a height of 20 m?
weqwewe [10]

Answer:

1. 1568 J

2. 0 J

3. 1176 J

Explanation:

PE = mgh

(PE = Potential Energy) = (m = mass)(g = gravitational force which is 9.8)(h = height)

1. (3)(9.8)(20) = 1568 J

2. PE = (3)(9.8)(0) = 0 J

3. (5)(9.8)(24) =  1176 J

4 0
2 years ago
Calculate the ph of the solution made by adding 0.50 mol of hobr and 0.30 mol of kobr to 1.00 l of water. the value of ka for ho
nikdorinn [45]
To fully understand the problem, we use the ICE table to identify the concentration of the species. We calculate as follows:

Ka = 2.0 x 10^-9 = [H+][OBr-] / [HOBr] 

HOBr  = 0.50 M 
KOBr  = 0.30 M = OBr-

<span>     HOBr + H2O <-> H+ + OBr- </span>
<span>I     0.50        -              0          0.30 </span>
<span>C       -x                        x             x 
</span>---------------------------------------------
<span>E(0.50-x)                    x       (0.30+x) </span>

<span>Assuming that the value of  x is small as compared to 0.30 and 0.50 </span>

<span>Ka = 2.0 x 10^-9 = x (0.30) / 0.50) </span>

<span>x = 3.33 x 10^-9 = H+</span>
pH = 8.48
3 0
3 years ago
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