Atomic number = 42
Name = Molybdenum
Atomic symbol = Mo
Group number = VI(B)6
Mo = Metal
How to find all valves of Z=42?
Here, we are going to find out the name, symbol and group numbers element with the following Z value and their classification as a metal, metalloid, or nonmetal.
The atomic number of the element is 42
Therefore, the name of the element is Molybdenum
The atomic symbol of the element is Mo
The group number of is VI(B)6
Mo is a metal
Hence, the element is Molybdenum
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Answer is: D. Cl (chlorine).
The ionization energy (Ei) is the minimum amount of energy required to remove the valence electron, when element lose electrons, oxidation number of element grows (oxidation process).
Barium, potassium and arsenic are metals (easily lost valence electrons), chlorine is nonmetal (easily gain electrons).
Alkaline metals (in this example, potassium) have lowest ionizations energy and easy remove valence electrons (one electron), earth alkaline metals (in this example, barium) have higher ionization energy than alkaline metals, because they have two valence electrons.
Nonmetals (in this example chlorine) are far right in the main group and they have highest ionization energy, because they have many valence electrons.
Answer:
D.
Explanation:
Carbon atoms are not strongly electronegative and tend to form covalent bonds.
The average speed : 3.07 m/s
<h3>Further explanation</h3>
Given
d1 = 2 km
t1 = 9 min
d2 = 1.5 km
t2 = 10 min
Required
The average speed
Solution
Average speed = total distance : total time
total distance :
= d1+d2
= 2+1.5
=3.5 km
total time :
= t1+t2
= 9 min + 10 min
= 19 min
Average speed :
= 3.5 km : 19 min
= 0.184 km/min
= 3.07 m/s
If the element is oxidized, then it's oxidation number would increase.
Let's say we have the following reaction.
2H2O --> O2 + 2H2
To the left, the oxidation number of O is -2, as it is bonded to two H, which is always H+. To the right, we have O2, and all gases have a oxidation number of 0 (zero). We say that O has been oxidized.
