Answer:
Evaporation and condensation are two processes through which matter changes from one state to another.
Explanation:
Answer:
SO3
Explanation:
Data obtained from the question include:
S = 40%
O = 59%
To obtain the empirical formula, do the following:
Divide the above by their molar mass as shown below:
S = 40/32 = 1.25
O = 59/16 = 3.69
Next, divide by the smallest as shown below:
S = 1.25/125 = 1
O = 3.69/1.25 = 3
Therefore, the empirical formula is SO3
This problem is providing a chemical equation between two hypothetical elements, X and Y and asks for the moles of X that are needed to produce 21.00 moles of D in excess Y. After the following work, the answer turns out to be 15.75 mol X:
<h3>Mole ratios:</h3><h3 />
In chemistry, one the most crucial branches is stoichiometry, which allows us to perform calculations with grams, moles and particles (atoms, molecules and ions). It is based on the concept of mole ratios, whereby the moles of a specific substance can be converted to moles of another one, say product to reactant, reactant to reactant, reactant to product and product to product.
<h3>Calculations:</h3>
In such a way, since 21.00 moles of D are given, we need the mole ratio of D to X in order to get the answer, which according to the reaction is 3:4 based on their coefficients in the reaction. Hence, we calculate the required as follows:
Learn more about mole ratios: brainly.com/question/15288923
<u>We are given:</u><u>_______________________________________________</u>
Volume of Gas (V) = 2.5L
Pressure (P) = 1.2 atm
Temperature (T) = 25°C OR 25+273 = 298 K
Universal Gravitational Constant (R) = 0.0821
<u>Solving for number of moles:</u><u>___________________________________</u>
From the Ideal Gas Equation,
PV = nRT
(1.2)(2.5) = n(0.0821)(298) [plugging the given values]
n = [(1.2)(2.5)] / [0.0821*298]
n = 300 / [298*8.21]
n = 0.12 moles
Hence, there are 0.12 moles of Oxygen in 2.5L of 1.2 atm gas when the temperature is 25°C
The spring constant determines how far the spring will stretch for a given applied force: <span>F=kx→k=<span>Fx</span></span><span>. If we place the same mass on the two springs, which means we have placed the same force on them, the one that stretches </span>least<span> has the largest spring constant.
Hope this helps!
</span>
