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Alex777 [14]
3 years ago
7

Can someone please explain Hydrogen bonding to me?

Chemistry
1 answer:
dmitriy555 [2]3 years ago
5 0

Answer: Hydrogen bonding: interaction involving a hydrogen atom located between a pair of other atoms having a high affinity for electron

Explanation:https://www.britannica.com/science/hydrogen-bonding

//Give thanks(and or Brainliest) if helpful (≧▽≦)//

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The reaction of ammonia and hydrogen chloride gas:
oee [108]
It's replacement reaction. Hope it helped
8 0
3 years ago
Complexes containing metals with d10 electron configurations are typically colorless because ________. Complexes containing meta
algol [13]

Answer:

there is no d electron that can be promoted via the absorption of visible light

Explanation:

One of the properties of transition elements is the possession of incompletely filled d orbitals. This property accounts for their unique colours.

The colours of transition metal compounds stem from d-d transition of electrons due to the presence of vacant d orbitals of appropriate energy to which electrons could be promoted.

For elements whose atoms have a d10 configuration, such vacant orbitals does not exist hence their compounds are not colored.

Sometimes, the colour of transition metal compounds stem from ligand to metal charge transfer(LMCT) for instance in KMnO4.

8 0
2 years ago
A sample of a compound is found to contain 40.0% carbon, 6.7% hydrogen, and 53.3% oxygen. What is the empirical formula of this
Shtirlitz [24]

Answer:

The empirical formula is CH2O, and the molecular formula is some multiple of this

Explanation:

In 100 g of the unknown, there are 40.0⋅g12.011⋅g⋅mol−1 C;  6.7⋅g1.00794⋅g⋅mol−1 H; and  53.5⋅g16.00⋅g⋅mol−1 O.

We divide thru to get, C:H:O = 3.33:6.65:3.34. When we divide each elemental ratio by the LOWEST number, we get an empirical formula of CH2O, i.e. near enough to WHOLE numbers. Now the molecular formula is always a multiple of the empirical formula; i.e. (EF)n=MF.So 60.0⋅g⋅mol−1=n×(12.011+2×1.00794+16.00)g⋅mol−1.Clearly n=2, and the molecular formula is 2×(CH2O) = CxHyOz.

5 0
1 year ago
Using ethanol and sodium or potassium cyanide as the sources of the carbon atoms, along with any necessary inorganic reagents, s
11Alexandr11 [23.1K]

Answer:

Please see attachment

Explanation:

Please see attachment

3 0
2 years ago
Plssssssssssssssssssmejepleplele
Leona [35]

Answer:

Yes the two of the answer is True

3 0
2 years ago
Read 2 more answers
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