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ira [324]
3 years ago
10

What would these molecules be labeled as? Can be (Alkane, Alkene Aromatic, Alcohol, Ester, Carboxylic acid, amine or amide) (Som

e can be more than one)​

Chemistry
1 answer:
erastovalidia [21]3 years ago
3 0

Answer:

Explanation:

C₄H₈ = Alkene because it contains one double bond

General formula of alkene is CnH2n .

CH₃CH₂CH₂CH₂CH₂NH₂ = Amine ( primary )

name is pentyl amine .

The third one is benzene which is aromatic in nature .

CH₃CH₂COOCH₂CH₂NH₂ .

It is an ester as follows

CH₃CH₂COCl + NH₂CH₂CH₂OH = CH₃CH₂COOCH₂CH₂NH₂

acid chloride + alcohol        =      ester + water .

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Write the balanced equation for the reaction of aqueous sodium carbonate and aqueous calcium chloride dihydrate to form solid ca
faltersainse [42]
<span>Na2CO3 (aq) + CaCl2H4O2 (aq) = CaCO3 (s) + 2 NaCl (aq) + 2 H2O (l)</span>
5 0
3 years ago
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The molecular weight of NaCl is 58.44 grams/moles. How many grams of NaCl are found in a beaket with 100 ml of a 0.0050 M soluti
Viktor [21]

Answer:

The mass of NaCl is 0.029 grams

Explanation:

Step 1: Data given

Molecular weight of NaCl = 58.44 g/mol

Volume of solution = 100 mL = 0.100 L

Molarity = 0.0050 M

Step 2: Calculate moles NaCl

Moles NaCl = molarity * volume

Moles NaCl = 0.0050 M * 0.100 L

Moles NaCl = 0.00050 moles

Step 3: Calculate mass NaCl

Mass NaCl = moles NaCl * molar mass NaCl

Mass NaCl = 0.00050 moles * 58.44 g/mol

Mass NaCl = 0.029 grams

The mass of NaCl is 0.029 grams

4 0
3 years ago
PLZ HELP! FAST! Extreme fast! PLZ! DUE TOMORROW! Please answer ASAP!
riadik2000 [5.3K]

29-23 is 6, so 6 degrees

3 0
3 years ago
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How many half-lives would something have gone through if you had 75% daughter product and 25% parent?
levacccp [35]

Answer:

Two Half-lives

Explanation:

Let number of Parent nuclei Initially present be X,

Then, finally \frac{X}{4} Parent nuclei Will remain with \frac{3X}{4} daughter nuclei.

In one half- life , parent nuclei becomes half of initial.

So, starting with X parent nuclei,

After one half-life, it will degrade to \frac{X}{2} .

After another half life , Parent nuclei will become half of \frac{X}{2}

Which is equal to \frac{X}{4}.

So, Parent nuclei have to go through Two half-lives.

6 0
3 years ago
3. What mass of copper could be deposited from a copper(II) Sulphate solution using a current of 5.0 A over 100 seconds? ( F =96
arsen [322]

Mass of copper : 0.165 g

<h3>Further explanation</h3>

Given

5.0 A over 100 seconds

Required

Mass of copper

Solution

Faraday's law:

<em>The mass of the substance formed at each electrode is proportional to the electric current flowing in the electrolysis</em>

<em />\tt W=\dfrac{e.i.t}{96500}<em />

e = Ar / valence = eqivalent weight

i = current

t = time

W = weight

CuSO₄ ----> Cu²⁺ + SO₄²⁻

Cu ----> Cu²⁺ + 2e

e = Ar/2

= 63,5/2 = 31,75

\tt W=\dfrac{31.75\times 5\times 100}{96500}=0.165~g

8 0
3 years ago
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