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ira [324]
3 years ago
10

What would these molecules be labeled as? Can be (Alkane, Alkene Aromatic, Alcohol, Ester, Carboxylic acid, amine or amide) (Som

e can be more than one)​

Chemistry
1 answer:
erastovalidia [21]3 years ago
3 0

Answer:

Explanation:

C₄H₈ = Alkene because it contains one double bond

General formula of alkene is CnH2n .

CH₃CH₂CH₂CH₂CH₂NH₂ = Amine ( primary )

name is pentyl amine .

The third one is benzene which is aromatic in nature .

CH₃CH₂COOCH₂CH₂NH₂ .

It is an ester as follows

CH₃CH₂COCl + NH₂CH₂CH₂OH = CH₃CH₂COOCH₂CH₂NH₂

acid chloride + alcohol        =      ester + water .

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Find the percentage composition of a compound that contains 1.94 g of carbon, 0.48 g of hydrogen, and 2.58 g of sulfur.
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Answer : The percentage composition of carbon, hydrogen and sulfur in a compound is, 38.8 %, 9.6 % and 51.6 % respectively.

Explanation :

To calculate the percentage composition of element in sample, we use the equation:

\%\text{ composition of element}=\frac{\text{Mass of element}}{\text{Mass of sample}}\times 100

Given:

Mass of carbon = 1.94 g

Mass of hydrogen = 0.48 g

Mass of sulfur = 2.58 g

First we have to calculate the mass of sample.

Mass of sample = Mass of carbon + Mass of hydrogen + Mass of sulfur

Mass of sample = 1.94 + 0.48 + 2.58 = 5.0 g

Now we have to calculate the percentage composition of a compound.

\%\text{ composition of carbon}=\frac{1.94g}{5.0g}\times 100=38.8\%

\%\text{ composition of hydrogen}=\frac{0.48g}{5.0g}\times 100=9.6\%

\%\text{ composition of sulfur}=\frac{2.58g}{5.0g}\times 100=51.6\%

Hence, the percentage composition of carbon, hydrogen and sulfur in a compound is, 38.8 %, 9.6 % and 51.6 % respectively.

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