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a_sh-v [17]
3 years ago
14

Evaporation and condensation

Chemistry
2 answers:
bagirrra123 [75]3 years ago
7 0

Answer:

Evaporation and condensation are two processes through which matter changes from one state to another.

Explanation:

Olegator [25]3 years ago
5 0

Answer:

Evaporation and condensation are two processes through which matter changes from one state to another. Matter can exist in three different states: solid, liquid, or gas. In evaporation, matter changes from a liquid to a gas. In condensation, matter changes from a gas to a liquid.

Explanation:

Hope this <em><u>Helped!</u></em> :D

Credit sourced from "kids.britannica.com"

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Stolb23 [73]
Mass of Lead is .00042 g
3 0
3 years ago
Draw the structure of the compound identified by the following simulated 1H and 13C NMR spectra. The molecular formula of the co
Luba_88 [7]

Answer:  4-allylanisole

Explanation: The doublets behind the 7 ppm belongs to the

para-substituted benzene ring. The three single-proton multi-plets around 5−6 ppm predicts that there has to be a single subsituted alkene group

A single plus a doublet around 3-4 ppm belongs to CH3 and CH2 Groups as they could be attached to the subsituted alkene group.

Moreover the interpretation of the NMR  that there is no peak with a higher intensity for >180 ppm represents an absence of Carbonyl group.

The Predicted Number is attached from a chemical database along with their peaks information

6 0
3 years ago
You could add solid KCl to the solution to precipitate out AgCl(s). What mass of KCl is needed to precipitate the silver ions fr
padilas [110]

Answer:

0.143 g of KCl.

Explanation:

Equation of the reaction:

AgNO3(aq) + KCl(aq) --> AgCl(s) + KNO3(aq)

Molar concentration = mass/volume

= 0.16 * 0.012

= 0.00192 mol AgNO3.

By stoichiometry, 1 mole of AgNO3 reacts with 1 mole of KCl to form a precipitate.

Number of moles of KCl = 0.00192 mol.

Molar mass of KCl = 39 + 35.5

= 74.5 g/mol

Mass = molar mass * number of moles

= 74.5 * 0.00192

= 0.143 g of KCl.

4 0
3 years ago
Lactose, C12H22O11, is a naturally occurring sugar found in mammalian milk. A 0.335 M solution of lactose in water has a density
Dmitry_Shevchenko [17]

The molality of the solution is 0.00037 m.

<h3>What is concentration?</h3>

The term concentration refers to the amount of solute in a solution.

We have the following information;

Molarity = 0.335 M

Density =  1.0432 g/mL

Temperature = 20 o C

The molality of the solution is obtained from;

m = 0.335 M ×  1.0432 g/mL/ 1000(1.0432 g/mL) - 0.335 M (342 g/mol)

m = 0.344/1043.2 - 114.57

m =  0.344/928.63

m = 0.00037 m

Learn more about molality of solution: brainly.com/question/4580605

5 0
2 years ago
The mass % of Ca in CaSO4 is 29.45%. To calculate the mass of Ca present in a 25.6-g sample of this compound, the correct proced
Rufina [12.5K]

Answer:

The correct answer is - 29.45 / 100 x 25.6 = 7.5392 grams

Explanation:

It is given in the question that in 100 gms of CaSO4 there are 29.45 grams of Ca present and there is 25.6 gram of total CaSO4 sample present, So, to calculate the exact value of calcium in this given sample is:

mass of Ca = total amount of sample*percentage of calcium in sample /100

M of Ca =25.6*29.45/100

M of Ca = 7.5392 grams

Thus, the correct procedure is given by 29.45 / 100 x 25.6 = 7.5392 grams

6 0
2 years ago
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