Why does the moon appear in the daytime
1 answer:
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Initial velocity, u = 4 m/s
acceleration due to gusts of wind = 3 m/s^2
time, t = 1 min = 60 s
Let distance travelled = S
From equation of motion,
Thus, the boat would have traveled 5640m after gusts picked up.
acceleration due to gusts of wind = 3 m/s^2
time, t = 1 min = 60 s
Let distance travelled = S
From equation of motion,
Thus, the boat would have traveled 5640m after gusts picked up.
Answer:
She covers the distance is 12 km.
The magnitude of displacement is 8.6 km.
The direction of her displacement is north east.
Explanation:
Given that,
Christina drives his moped 7 kilometers North and stop for lunch and then drive 5 km east.
We need to calculate the total distance
Using formula of distance
Put the value into the formula
We need to calculate the magnitude of displacement
Using formula of displacement
The direction of her displacement is north east.
Hence, She covers the distance is 12 km.
The magnitude of displacement is 8.6 km.
The direction of her displacement is north east.
Answer: The velocity at different marked time points are given as
t1 = -
t2 = +
t3 = +
t4 = -
t5 = 0
Explanation:
The slope of the tangent of the curve indicates the instantaneous velocity. So if the slope of the tangent is positive, that Is, the tangent makes a positive angle (above the horizontal axis) with the horizontal
axis, then the velocity at this point is positive, and if the slope of the tangent is negative, that is the tangent makes a negative angle with the horizontal axis (below the horizontal axis), then the velocity at this point is negative.
When the tangent of the line is parallel to the horizontal axis, the velocity is 0.
From the position-time graph attached, the sign on the instantaneous velocity for each time marked on the graph is given below
t1 = -
t2 = +
t3 = +
t4 = -
t5 = 0
QED!
