Three forces are applied to an object, as shown in the diagram below. F1 = 30 N, F2 = 34 N, F3 = 20 N, d1 = 25 mm, d2 = 20 mm, d
3 = 10 mm, θ3 = 500. What is the resultant torque around the point 'x', in units of Nm?
1 answer:
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Answer:
(a) The speed of the first particle is 1.75 m/s. The speed of the second particle is 6.9 m/s after the collision.
(b) The speed of the first particle is 3.45 m/s in the negative direction. The speed of the second particle is 1.73 m/s.
(c) The final kinetic energy of the incident particle in part (a) and part(b) is 0.0031 J and 0.011 J, respectively.
Explanation:
(a)
In an elastic collision, both momentum and energy is conserved.
Combining these equations will give the speed of the second particle.
We can use this to find the speed of the first particle.
(b)
If m_2 = 10g.
The minus sign indicates that the first particle turns back after the collision.
(c)
The final kinetic energy of the particle in part (a) and part (b) is