The minimum velocity of the Salmon jumping at the given angle is 12.3 m/s.
The given parameters;
- height of the waterfall, h = 0.432 m
- distance of the Salmon from the waterfall, s = 3.17 m
- angle of projection of the Salmon, = 30.8º
The time of motion to fall from 0.432 m is calculated as;
The minimum velocity of the Salmon jumping at the given angle is calculated as;
Thus, the minimum velocity of the Salmon jumping at the given angle is 12.3 m/s.
Learn more here: brainly.com/question/20064545
The second law states that the total entropy can never decrese over time for an isolated system
Answer:
The positive displacement from the midpoint of its motion at the speed equal one half of its maximum speed is 3.56 cm.
Explanation:
Maximum speed is :
v (max) = Aω
Speed v at any displacement y is given by
= 
(
- 
) ........................................................ i
And,
v = 
v (max)
or, 2 × v = Aω .................................................... ii
Eliminating ω from equations i and ii,
= ( - )
or, = (
) =() 
or, y = 3.56 cm.
For a neutral atom number of electrons equals number of protons, in other for the net charge of the atom to be zero...
no. of electrons = 12
