B.
technically it would depend if the resistors were in series or parallel but B is the answer.
(a) At a corresponding hill on Earth and a lesser gravity on planet Epslion, the height of the hill will cause a reduction in the initial speed of the snowboarder from 4 m/s to a value greater than zero (0).
(b) If the initial speed at the bottom of the hill is 5 m/s, the final speed at the top of the hill be greater than 3 m/s.
<h3>
Conservation of mechanical energy</h3>
The effect of height and gravity on speed on the given planet Epislon is determined by applying the principle of conservation of mechanical energy as shown below;
ΔK.E = ΔP.E
¹/₂m(v²- u²) = mg(hi - hf)
¹/₂(v²- u²) = g(0 - hf)
v² - u² = -2ghf
v² = u² - 2ghf
where;
- v is the final velocity at upper level
- u is the initial velocity
- hf is final height
- g is acceleration due to gravity
when u² = 2gh, then v² = 0,
when gravity reduces, u² > 2gh, and v² > 0
Thus, at a corresponding hill on Earth and a lesser gravity on planet Epslion, the height of the hill will cause a reduction in the initial speed of the snowboarder from 4 m/s to a value greater than zero (0).
<h3>Final speed</h3>
v² = u² - 2ghf
where;
- u is the initial speed = 5 m/s
- g is acceleration due to gravity and its less than 9.8 m/s²
- v is final speed
- hf is equal height
Since g on Epislon is less than 9.8 m/s² of Earth;
5² - 2ghf > 3 m/s
Thus, if the initial speed at the bottom of the hill is 5 m/s, the final speed at the top of the hill be greater than 3 m/s.
Learn more about conservation of mechanical energy here: brainly.com/question/6852965
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Answer:
Their velocity after the collision is 1.2 m/s, to the right.
Explanation:
Given;
mass of the blue car, m₁ = 2 kg
initial velocity of the blue car, u₁ = 6 m/s
mass of the red car, m₂ = 3 kg
initial velocity of the red car, u₂ = 2 m/s
let the blue car moving to the right be in positive direction
also, let the red car moving to the left be in negative direction
Apply the principle of conservation of linear momentum for inelastic collision.
m₁u₁ - m₂u₂ = v(m₁ + m₂)
where;
v is their velocity after the collision
(2 x 6) - (3 x 2) = v(2 + 3)
12 - 6 = 5v
6 = 5v
v = 6/5
v = 1.2 m/s, to the right
Therefore, their velocity after the collision is 1.2 m/s, to the right.
