We know that
a(n)=4n+1
To find the sum of the first n<span> terms of an arithmetic series
use the formula
</span><span><span>Sn</span>=<span>n(<span>a1</span> + <span>an</span>)/2
</span></span>a1--------------> is the first term
an--------------> is the last term
n--------------- > <span>is the number of terms
</span>we have that
a1------------> 4*(1)+1=5
a30----------> 4*(30)+1=121
n------------- > 30
S30=30*(5 + 121)/2=1890
the answer is 1890
Answer:
answer is 27 hope it helps
The answer could be D- pq. It's not from the center of the circle.
Answer:
y=3
Step-by-step explanation:
Let's solve your equation step-by-step.
5y−3y+1=7
Step 1: Simplify both sides of the equation.
5y−3y+1=7
5y+−3y+1=7
(5y+−3y)+(1)=7(Combine Like Terms)
2y+1=7
2y+1=7
Step 2: Subtract 1 from both sides.
2y+1−1=7−1
2y=6
Step 3: Divide both sides by 2.
2y
/2
=
6
/2
y=3
12:00-9:30 = 2:30
12:30+8:30 = 8:30
2:30 + 8:30 = 11:00
11 total hours elapsed
