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Vitek1552 [10]
3 years ago
5

Two electric charges are moved so that they are twice as far apart as they had originally been. Is the force they experience fro

m each other now half the original force? Explain.
Physics
1 answer:
Natasha_Volkova [10]3 years ago
5 0

Answer:

No.

Explanation:

The force that two particle experience is inversely proportional to the sqare of the distance, this is:

F \  \alpha \  \frac{1}{D^{2}} for a distance D

If we move them so that D is doubled:

\frac{1}{2^{2}.D^{2}  }= \frac{1}{4} \eq  \frac{1}{.D^{2}  } \eq

Then the force they experience is one fourth of the original.

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<h3><u>Given </u><u>:</u><u>-</u><u> </u></h3>

  • A certain circuit is composed of two series resistors
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<h3><u>To </u><u>Find </u><u>:</u><u>-</u></h3>

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<h3><u>Let's </u><u>Begin </u><u>:</u><u>-</u></h3>

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<u>That </u><u>is</u><u>, </u>

Rn in series = R1 + R2 + R3.....So on

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<u>According </u><u>to </u><u>the </u><u>question</u><u>, </u>

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