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expeople1 [14]
3 years ago
6

What is the kinetic engery of a baseball five feet above the ground when it has already fallen 32 feet

Physics
1 answer:
mylen [45]3 years ago
6 0
The answer is 25 ...
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How does energy release from the sun reach Earth? How does the sun's energy interact with Earth's atmosphere and hydrosphere?
kotegsom [21]
Because of the water
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2 years ago
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Two satellites revolve around the Earth. Satellite A has mass m and has an orbit of radius r. Satellite B has mass 6m and an orb
melomori [17]

Answer:

aaaaa

Explanation:

M = Mass of the Earth

m = Mass of satellite

r = Radius of satellite

G = Gravitational constant

F=G\frac{Mm}{r^2}

F=G\frac{M6m}{r_b^2}

G\frac{Mm}{r^2}=G\frac{M6m}{r_b^2}\\\Rightarrow \frac{1}{r^2}=\frac{6}{r_b^2}\\\Rightarrow \frac{r_b^2}{r^2}=6\\\Rightarrow \frac{r_b}{r}=\sqrt{6}\\\Rightarrow r_b=2.44948r

r_b=2.44948r

8 0
3 years ago
Urgent<br> Please write the complete answer
Crazy boy [7]

Multiply field strength (N/kg) by mass (kg) to get weight (N)

At the start, the car is carrying

4.7 kg * (9.8 N/kg) = 46.06 N

of fuel.

At the end, it is carrying

3.0 kg * (9.8 N/kg) = 29.4 N.

Assuming the car remains completely intact, its weight was reduced by

46.06 N - 29.4 N = 16.66 N.

5 0
3 years ago
What is the maximum speed with which a 1200-kg car can round a turn of radius 94.0 m on a flat road if the coefficient of static
JulijaS [17]

Answer:

<h2>          v= 21.47m/s      </h2>

Explanation:

For the car to turn at the about the centripetal force must not be greater than the static friction between the tires and the road

we will use the expression relating centripetal force and static friction below

let U represent the coefficient of static friction

Given that

U= 0.50

mass m= 1200-kg

radius r= 94.0 m

Assuming g= 9.81 m/s^2

U*m*g=\frac{mv^2}{r}

U*g=\frac{v^2}{r}

substituting our given data in to expression we can solve for the speed V

0.5*9.81=\frac{v^2}{94}

making v the subject of formula we have

0.5*9.81=\frac{v^2}{94}\\\v= \sqrt{0.5*9.81*94} \\\\v= \sqrt{461.07} \\\\v= 21.47

v= 21.47m/s

<em><u>hence the maximum velocity of the car is 21.47m/s</u></em>

7 0
3 years ago
How do you get rid of depression?
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A sicitrist might help you or go to a doctor and get some marijawana
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