Answer:
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Explanation:
M = Mass of the Earth
m = Mass of satellite
r = Radius of satellite
G = Gravitational constant




Multiply field strength (N/kg) by mass (kg) to get weight (N)
At the start, the car is carrying
4.7 kg * (9.8 N/kg) = 46.06 N
of fuel.
At the end, it is carrying
3.0 kg * (9.8 N/kg) = 29.4 N.
Assuming the car remains completely intact, its weight was reduced by
46.06 N - 29.4 N = 16.66 N.
Answer:
<h2> v= 21.47m/s </h2>
Explanation:
For the car to turn at the about the centripetal force must not be greater than the static friction between the tires and the road
we will use the expression relating centripetal force and static friction below
let U represent the coefficient of static friction
Given that
U= 0.50
mass m= 1200-kg
radius r= 94.0 m
Assuming g= 9.81 m/s^2


substituting our given data in to expression we can solve for the speed V

making v the subject of formula we have

v= 21.47m/s
<em><u>hence the maximum velocity of the car is 21.47m/s</u></em>
A sicitrist might help you or go to a doctor and get some marijawana