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4 years ago

Will mark brainliest! (problem below)

Mathematics

2 answers:

Mamont248 [21]4 years ago

6 0

Answer:

Helena

Step-by-step explanation:

7y^2z is not modified in either the answer or the question.

6yz^2 - 3yz^2 = 3yz^2

-5 + 2 = - 3

Combining the the partial answers, you get

7y^2 + 3yz^2 - 3

which is the same as the original question.

Vlad [161]4 years ago

4 0

Answer:

Joe

Hope this helps!

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Answer:

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Step-by-step explanation:

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3 years ago

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4 0

4 years ago

Read 2 more answers

A cylinder is cross-sectioned horizontally (from side to side).what shape does the resulting cross section form

Xelga [282]

Answer: I dont know im sorry

Step-by-step explanation:

8 0

3 years ago

M) Factorise:<br>x2/9+1+9/x2

BARSIC [14]

Answer:

Cannot be factored

Step-by-step explanation:

Given

$\frac{x^2}{9} + 1 + \frac{9}{x^2}$

Required

Factorize

Take LCM

$\frac{x^2}{9} + 1 + \frac{9}{x^2} = \frac{x^4+9x^2+81}{9x^2}$

<em>The expression cannot be factored</em>

3 0

3 years ago

A lot of laptop computers contain 20 good ones and 3 defective ones. If two are selected and tested, find the probability that a

GarryVolchara [31]

Answer: $\dfrac{63}{253}$

Step-by-step explanation:

Given : Number of good laptops =20

Number of defective ones=3

Total laptops =23

If 2 laptops were selected, then the probability that none of them was defective would be = $\dfrac{^{20}C_2}{^{23}C_2}$

$=\dfrac{\dfrac{20!}{2!18!}}{\dfrac{23!}{2!21!}}=\dfrac{19\times20}{23\times22}\\\\=\dfrac{190}{253}$

The probability that at least one will be defective= 1- P(none of them is defective)

$=1-\dfrac{190}{253}=\dfrac{63}{253}$

Hence, the probability that at least one will be defective. $=\dfrac{63}{253}$

4 0

4 years ago