Answer:Elena uses 12 red beads to make 4 bracelets. How many red beads will Elena need to make 12 bracelets? How many red beads will Elena need to make 20 bracelets? You can make a table showing the number of bracelets that can be made with different numbers of red beads. The pairs of numbers in each column show the ratio ofred beads to bracelets. Notice the ratios are all equivalent.
Number of Red Beads 3 6 12 24 36 48 60 72 Number of Bracelets 1 2 4 8 12 16 20 24
The table shows Elena will need 36 red beads to make 12 bracelets. Elena will need 60 red beads to make 20 bracelets. James said that he would need 25 red beads to make 75 bracelets. Is he correct? How did he get that answer?
Step-by-step explanation:
<u>7.1 cm long is the arc</u><u> intersected by a central angle .</u>
What is length of an arc?
- The arc length of a circle can be calculated with the radius and central angle using the arc length formula.
- Length of an Arc = θ × r, where θ is in radian. Length of an Arc = θ × (π/180) × r, where θ is in degree.
Given,
Central angle = π / 2
radius = 4.5 cm
we apply formula of length of arc.
length of the arc = angle × radius
= (π/2) × (4.5 cm)
Now put value of π = 3.14
length of the arc = (3.14 / 2) × (4.5) cm
= 7.065 cm ≈ 7.1 cm
Therefore, 7.1 cm long is the arc intersected by a central angle .
Learn more about<u> </u> length of an arc
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Answer:
18 years
Step-by-step explanation:
The formula for computing accrued amount A for a principal of P at an interest rate of r(in decimal) compounded n times in a year for t years is given by
![A = P(1 + \frac{r}{n})^{nt}](https://tex.z-dn.net/?f=A%20%3D%20P%281%20%2B%20%5Cfrac%7Br%7D%7Bn%7D%29%5E%7Bnt%7D)
Note that r is percentage converted to decimal. So 3% = 3/100 = 0.03
We can rearrange the above equation to:
![\frac{A}{P} = (1 + \frac{r}{n})^{nt}](https://tex.z-dn.net/?f=%5Cfrac%7BA%7D%7BP%7D%20%3D%20%281%20%2B%20%5Cfrac%7Br%7D%7Bn%7D%29%5E%7Bnt%7D)
Taking logs on both sides
![log(\frac{A}{P}) = log(1 + \frac{r}{n})^{nt}](https://tex.z-dn.net/?f=log%28%5Cfrac%7BA%7D%7BP%7D%29%20%3D%20log%281%20%2B%20%5Cfrac%7Br%7D%7Bn%7D%29%5E%7Bnt%7D)
This gives
![log(\frac{A}{P}) =nt \times log(1 + \frac{r}{n})\\So,\\nt = \frac{log(\frac{A}{P})}{ log(1 + \frac{r}{n})}](https://tex.z-dn.net/?f=log%28%5Cfrac%7BA%7D%7BP%7D%29%20%3Dnt%20%5Ctimes%20log%281%20%2B%20%5Cfrac%7Br%7D%7Bn%7D%29%5C%5CSo%2C%5C%5Cnt%20%3D%20%5Cfrac%7Blog%28%5Cfrac%7BA%7D%7BP%7D%29%7D%7B%20log%281%20%2B%20%5Cfrac%7Br%7D%7Bn%7D%29%7D)
In this particular problem, n = 4, , A= 9600, P = 5600, r =0.03, so r/n = 0.03/4 = 0.0075
1 + r/n = 1+0.0075 = 1.0075
4t = log(9600/5600)/log(1.0075) = log(1.714) / log(1.0075) = 0.234 /0.00325 = 72
t = 72/4 = 18 years
Answer:
36*5+80 =260
Step-by-step explanation:
hope this helps
Answer:
-x^2 - 7x + 4
Step-by-step explanation:
2x(x - 1) - 3x^2 - (5x - 4)
= 2x^2 - 2x - 3x^2 - 5x + 4
Adding like terms, we get:-
-x^2 - 7x + 4 (answer).