Answer:
$15600
Step-by-step explanation:
Minimum number of samples can be calculated using the formula:
N≥
where
- N is the sample size
- z is the corresponding z-score for 95% confidence level (1.96)
- s is the standard deviation of the calorie consumption (450 cal.)
- ME is the margin of error that the researcher is willing to accept. (50 cal)
N≥
=311.2
Therefore, minimum required sample size for 50 cal standard error in 95% confidence is 312
Since the survey costs $50 for each person then the survey costs minimum
50*312=$15600
Answer:
3.50 one thats it
if you need anyother help im here for you um yea...im not really in colage i just found this place at imn class lol im in 6th grade and am 11 years old lol thats my live oh and my dad is abusive lol yea...
Step-by-step explanation:
Answer:
88%
Step-by-step explanation:
60/500 people use a coupon
440/500 people do not use a coupon.
We can reduce the fraction: 440/500
220/250
then again
110/125
and /5 again.
22/25
then both sides by 4.
88/100
there, 88%
Answer:
45%
Step-by-step explanation:
Here, we want to know the probability of a randomly selected yard having 6 or more than 6 trees
To get this, we simply add up the probability of 6 yards and above
That is the probability of 6, 8 , 10 and 12 yards
This is obtainable from the histogram
We then proceed to add up from the graph
What we have is;
0.05 + 0.25 + 0.10 + 0.05
= 0.10 + 0.10 + 0.25 = 0.45
This is same as 45/100 which is otherwise 45%
