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valentinak56 [21]
3 years ago
10

Question

Mathematics
1 answer:
ser-zykov [4K]3 years ago
3 0

Answer:

2 jell djeeujdeieuwieue

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In the figure below angle y and angle x form vertical angles.Angle y forms a straight line with 60° angle and 70° angle right an
xxMikexx [17]

Answer:

x = 50

Step-by-step explanation:

The angles 70, 60, and y are supplementary, meaning that the sum of them is 180.  Therefore,

70 + 60 + y = 180 and

y = 50

That means that x = 50 as well, since vertical angles are congruent

3 0
3 years ago
Write the equation of the line in slope-intercept form.
scoundrel [369]

Answer: The equation of the line in slope-intercept form is “y = 4/3x + 4.”

5 0
2 years ago
Need help with #1 #4 #7 plz giving 15 points
valentina_108 [34]

Answer:

Q1:  p = - 33

Q2: d = - 99

Q3: t = - 13

Step-by-step explanation:

Q1: $ \textbf{-} \frac{\textbf{p}}{\textbf{3}} \hspace{1mm}  \textbf{-} \hspace{1mm}  \textbf{8} \hspace{1mm}  \textbf{=} \hspace{1mm} \textbf{3}

We solve this taking LCM.

We get: $ \frac{-p - 24}{3} = 3 $

$ \implies - p - 24 = 9 $

$ \implies \textbf{p} \hspace{1mm}  \textbf{=} \hspace{1mm}  \textbf{- 33} $

Q4: $ \frac{\textbf{d}}{\textbf{11}} \hspace{1mm}  \textbf{-} \hspace{1mm}  \textbf{4} \hspace{1mm}  \textbf{=} \hspace{1mm}  \textbf{- 13} $

Again we proceed like Q1 by taking LCM.

We get: $ \frac{d - 44}{11} = - 13 $

$ \implies d - 44 = - 13 \times 11 = - 143 $

$ \implies d = - 143 + 44 $

$ \implies \textbf{d} \hspace{1mm}  \textbf{=} \hspace{1mm}  \textbf{- 99} $

Q7: 5t + 12 = 4t - 1

We club the like terms on either side.

$ \implies 5t - 4t = - 1 - 12 $

$ \implies (5 -4)t = - 13 $

$ \implies \textbf{t} \hspace{1mm}  \textbf{=} \hspace{1mm}  \textbf{- 13} $

Hence, the answer.

7 0
3 years ago
-4004 + 2023 – 24x2 – 2 / – 2x2 + 2x + 1?
Kamila [148]

Answer:

388.5/x

Step-by-step explanation:

multiply:

(-4004+2023-48-2)/ -4 + 2x +1

Simplify:

-2031/ -3 +2x

divide by -3

677/2x

388.5 / x

as simple as you can go

hope this helps!

5 0
3 years ago
The scale of a map is 1 in. = mi. Find each length on the map
WITCHER [35]

The question gives the relationship to be

1in=21mi

We will interpolate to solve the question.

First Question: 147 mi

\begin{gathered} \text{If 1 in = 21 mi} \\ x\text{ in = 147 mi} \end{gathered}

Cross multiplying,

undefined

7 0
1 year ago
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