The freezing point of water is 32°F, 0°C.
Answer: The rising and setting of the Sun.
The appearance and disappearance of the Moon.
Changes in season.
Appearance and disappearance of the Stars.
Explanation: The rising and setting of the Sun helps can be used as a standard to determine time since the rissing and setting of the Sun occurs at similar time and interval in a given geographical ocation.
The appearance and disappearance of the Moon which occurs during the night and early hours of the morning is similar in a given geographical locationation so it can be used as a standard for Time.
Change in season is another natural phenomenon which occurs at similar times in a given geographical location like Winter/summer, rainy/dry etc can be used as standards for time.
The appearance and disappearance of the Stars can also b used as standards for time in a given geographical location.
Answer:
86MJ
Explanation:
THE TOPIC FROM WHICH THE QUESTION IS OBTAINED IS WORK, ENERGY AND POWER
- Power is defined as the time rate of doing work.
- Power =
- If the energy use is in joules and the time is in seconds, then power is a measure of watts.
1watt = 1 joule per second.
- According to the question, we need to find how much energy does one house use during each 24 hour day ( Already given time = 24hours) when the average rate of electric energy consumption in one house is 1.0 kW ( we have been given power = 1kW).
- Power = 1kW = 1 × 10³W
- Time = 24hours = 24 ×3600 = 86400seconds.
- It is important we have our time in seconds so as to be consistent with unit and dimension
Power =
1 × 10³W =
- Energy used =1 × 10³W × 86400
- Energy used = 86400000J = 86.4 ×
W = 86.4MJ
The question requested the answer in 2 significant figures and the answer is 86MJ
1. a=(v-v0)/t
a=14 m/s / 2s
a=7 m/s^2
2. <span>a=(v-v0)/t
</span>a=(30 m/s - 0 m/s) / 12 s
a=2.5 m/s^2
3. <span>a=(v-v0)/t
a=(37 m/s - 22 m/s) / 2 s
a= 7.5 m/s^2
4. </span><span>a=(v-v0)/t
a=(12 km/s - 0 km/s)/8 s
a=1.5 km/s^2
etc</span>
We know avogadro's number = 6.023 x 10²³
1 amu = 1 atomic mass unit = 1/ (6.023 x 10²³) gm = 1.66 x 10⁻²⁴grams
<span>Now, to convert amu to grams,
131.29 amu = 131.29 x 1.66 x 10</span>⁻²⁴grams
<span>= 2.18 x 10</span>⁻²²<span> grams is the answer</span>
