Answer:
Explanation:
Given that:
Electrical field E =
square side l = 5.0 m
Area A = 5.0 * 5.0
= 25.0 m²
Angle ( θ ) between area vector and E = (90° - 60°)
= 30°
The flux can now be determined by using the expression
=
=
=
=
The element in an incandescent light bulb that releases light energy is? A- a phosphor, B- mercury vapor, C- a thin tungsten fil
1 answer:
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