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3 years ago

7

If a bowling ball ball was released from the 6th floor of a hotel room 22 meters from the ground, at what velocity would the bal

l be moving just before it hits the head of the man who is 1.5 meters tall? Solve using kinematic equations, unknown values, and SOHCAHTOA.

1 answer:

dexar [7]3 years ago

3 0

Explanation:

Given:

y₀ = 22 m

y = 1.5 m

v₀ = 0 m/s

a = -9.8 m/s²

Find: v

v² = v₀² + 2a (y − y₀)

v² = (0 m/s)² + 2 (-9.8 m/s²) (1.5 m − 22 m)

v = -20.0 m/s

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