Question

A plane electromagnetic wave travels northward. At one instant, its electric field has a magnitude of 9.6 V/m and points eastward. What are the magnitude (in T) and direction of the magnetic field at this instant?

Answer 1

Answer:

The values is  $B = 3.2 *10^{-8} \ T$

The  direction is out of the plane

Explanation:

From the question we are told that

  The  magnitude of the electric field is  $E = 9.6 \ V/m$

 

The  magnitude of the magnetic field is mathematically represented as

       $B = \frac{E}{c}$

where c is the speed of light with value

      $B = \frac{ 9.6}{3.0 *10^{8}}$

     $B = 3.2 *10^{-8} \ T$

Given that the direction off the electromagnetic wave( c ) is  northward(y-plane ) and  the electric field(E) is eastward(x-plane ) then the magnetic field will be acting in the out of the page  (z-plane  )