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Andrei [34K]
3 years ago
7

A plane electromagnetic wave travels northward. At one instant, its electric field has a magnitude of 9.6 V/m and points eastwar

d. What are the magnitude (in T) and direction of the magnetic field at this instant?
Physics
1 answer:
lara31 [8.8K]3 years ago
3 0

Answer:

The values is  B  = 3.2 *10^{-8} \  T

The  direction is out of the plane

Explanation:

From the question we are told that

  The  magnitude of the electric field is  E  =  9.6 \  V/m

 

The  magnitude of the magnetic field is mathematically represented as

       B  = \frac{E}{c}

where c is the speed of light with value

      B  = \frac{ 9.6}{3.0 *10^{8}}

     B  = 3.2 *10^{-8} \  T

Given that the direction off the electromagnetic wave( c ) is  northward(y-plane ) and  the electric field(E) is eastward(x-plane ) then the magnetic field will be acting in the out of the page  (z-plane  )

     

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Factors Affecting the Value of g

As the radius of the earth increases from the poles to the equator, the value of g becomes greater at the poles than at the equator.

As we go at large heights, value of g decreases.

To Calculate the Value of g

Value of universal gravitational constant, G = 6.7 × 10–11 N m2/ kg2,

Mass of the earth, M = 6 × 1024 kg, and

Radius of the earth, R = 6.4 × 106 m

Putting all these values in equation (iii), we get:

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Difference between Gravitation Constant (G) and Gravitational Acceleration (g)

S. No.

Gravitation Constant (G)

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It is a scalar quantity.

It is a vactor quantity.

3.

Its value remains constant always and everywhere.

Its value varies at various places.

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Its unit is Nm2/kg2.

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