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3 years ago

12

Can a falling object reach terminal velocity in outer space?

2 answers:

yan [13]3 years ago

6 0

Answer: lth air resistance acting on an object that has been dropped, the object will eventually reach a terminal velocity, which is around 53 m/s (195 km/h or 122 mph) for a human skydiver (on the moon, the gravitational acceleration is much less on earth, approximately 1.6 m/s2.)

Explanation:

Triss [41]3 years ago

4 0

Answer:

There is no gravity in outer space so how will any object fall in the first place

Also the principle of terminal velocity is limited to free fall where the acceleration is equal to the gravity of the planet

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When particles vibrate so quickly they break free from their fixed positions, matter is:

Sonbull [250]

Condensing because when particles vibrate they condense.

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3 years ago

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A ball rolls from x = - 5m to x = 0m in 1 second . What was its average velocity? (Units = m/s) Don't forget: velocities and dis

katrin2010 [14]

Answer:

+ 5 m/s

Explanation:

change in displacement = ΔX=final position - initial position

ΔX = 0-(-5) =0+5 =+ 5 m

average velocity = ΔX/t

= +5/1

= + 5 m/s

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3 years ago

Suppose that you are swimming in a river while a friend watches from the shore. In calm water, you swim at a speed of 1.25 m/s .

aliya0001 [1]

Answer: The observing friend will the swimmer moving at a speed of 0.25 m/s.

Explanation:

Let <em>S</em> be the speed of the swimmer, given as 1.25 m/s

Let $S_{0}$ be the speed of the river's current given as 1.00 m/s.

Note that this speed is the magnitude of the velocity which is a vector quantity.

The direction of the swimmer is upstream.

Hence the resultant velocity is given as, $S_{R}$ = S — S 0 $S_{0}$

$S_{R}$ = 1.25 — 1

$S_{R}$ = 0.25 m/s.

Therefore, the observing friend will see the swimmer moving at a speed of 0.25 m/s due to resistance produced by the current of the river.

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3 years ago

The velocities of light in air and glass are 3.0 x 10^8ms and 2.0×10^8ms respectively. If the angle of refraction is 30°, the si

JulijaS [17]

Answer:

0.75

Explanation:

$refractive \: index \: = \frac{3.0 \times {10}^{2} }{2.0 \times {10}^{2} }$

= 1.5

$refractive \: index = \frac{ \sin(angle \: of \: incidence) }{ \sin(angle \: of \: refraction) }$

$1.5 = \ \frac{ \sin(i) }{ \sin(30) }$

1.5 × ½ = sin(i)

$\sin(i) = 0.75$

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3 years ago

LAST ONE! ASAP PLEASE

Doss [256]

Answer:

There are so many questions which one you don't know

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