Answer
given,
difference between the two consecutive maximum
λ = 0.870 - 0.540
λ = 0.33 m
speed of sound = 340 m/s
b) frequency of the sound
v = f x λ
340 = f x 0.33
f = 1030.3 Hz
a) phase difference
the expression of phase difference is given by
now,
Answer:
a) Time period is 3.3 seconds
b) The frequency is 0.3030 Hz
c) amplitude is 0.25 m
d) maximum speed is 0.476 m/s
Explanation:
Given the data in the question;
a) Period
Time Period T = Time taken for one oscillation
T = 33s / 10 = 3.3 seconds
Therefore, Time period is 3.3 seconds
b) Frequency
we know that frequency is the inverse of time period
so;
Frequency f = 1/T = 1 / 3.3 s
Frequency f = 0.3030 Hz
Therefore, The frequency is 0.3030 Hz
c) amplitude
amplitude A = ( 60 cm - 10 cm )
A = × 50 cm
A = 25 cm
A = 0.25 m
Therefore, amplitude is 0.25 m
d) maximum speed of the glider
maximum speed = ωA
and ω = 2π/T
so maximum speed =
A
so we substitute
so maximum speed =
× 0.25 m
so maximum speed = 0.476 m/s
Therefore, maximum speed is 0.476 m/s