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Karo-lina-s [1.5K]
3 years ago
14

I NEED HELP PLEASE THANKS! :)

Physics
1 answer:
Nady [450]3 years ago
7 0

Answer:

0.962 s

Explanation:

Speed = frequency × wavelength

v = fλ

2.60 m/s = f (2.50 m)

f = 1.04 Hz

Period = 1 / frequency

T = 1/f

T = 1 / (1.04 Hz)

T = 0.962 s

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Which of the following does not dissolve in water​
Anna11 [10]

Answer:

Sand,Mud

Explanation:

Sugar and salt are examples of soluble substances. Substances that do not dissolve in water are called insoluble. Sand and flour are examples of insoluble substances.

6 0
3 years ago
A dart gun suspended by strings hangs in equilibrium. The mass of the gun is 355 grams, not including a dart. The gun fires a 57
gogolik [260]

Answer:

dart's speed is 11.77 m/s

Explanation:

given data

mass of the gun m = 355 gram = 0.355 kg

height = 18.3 centimeters = 0.183 m

dart = 57.0 gram = 0.057 kg

to find out

dart's speed

solution

we apply here law of conservation of energy that is express as

mgh = 0.5 × m × v²      ...........1

so speed of gun will be here as

V = \sqrt{2gh}     ..................2

V = \sqrt{2*9.8*0.183}

V =  1.89 m/s

and

now we find speed of dart by use law of conservation of momentum that is

M×V  = m×v         ...............3

so speed of the dart is

v = \frac{M*V}{m}

v =  \frac{0.355*1.89}{0.057}

v = 11.77 m/s

so dart's speed is 11.77 m/s

5 0
3 years ago
The cycle of day and night is a result of Earth’s spinning on its axis, which is Earth’s .
nekit [7.7K]

Answer:

Rotation

Explanation:

i did the test Gl.

5 0
3 years ago
The Hubble Space Telescope orbits the Earth at approximately 612,000m altitude. Its mass is 11,100 kg and the mass of earth is 5
nexus9112 [7]

Answer:

7.55 km/s

Explanation:

The force of gravity between the Earth and the Hubble Telescope corresponds to the centripetal force that keeps the telescope in uniform circular motion around the Earth:

G\frac{mM}{R^2}=m\frac{v^2}{R}

where

G=6.67\cdot 10^{-11} m^3 kg^{-1} s^{-2} is the gravitational constant

m=11,100 kg is the mass of the telescope

M=5.97\cdot 10^{24} kg is the mass of the Earth

R=r+h=6.38\cdot 10^6 m+612,000 m=6.99\cdot 10^6 m is the distance between the telescope and the Earth's centre (given by the sum of the Earth's radius, r, and the telescope altitude, h)

v = ? is the orbital velocity of the Hubble telescope

Re-arranging the equation and substituting numbers, we find the orbital velocity:

v=\sqrt{\frac{GM}{R}}=\sqrt{\frac{(6.67\cdot 10^{-11})(5.97\cdot 10^{24} kg)}{6.99\cdot 10^6 m}}=7548 m/s=7.55 km/s

6 0
3 years ago
Which f the following are true for gravity
alisha [4.7K]

Answer:

Explanation:

number A

6 0
3 years ago
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