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3 years ago

A satellite’s velocity is 30000m/s. After 60 secs, it’s velocity shows to 15000m/a. What is the satellite’s acceleration?

Physics

1 answer:

Orlov [11]3 years ago

4 0

Answer:

Acceleration = 9 × 10^5 m/s^2 ( deceleration )

Explanation:

From the first equation of motion:

V = u + at

15000 = 30000 + 60a

a = ( 15000-30000)/60

a = 9 × 10^5 m/s^2

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I need a little help with this

Mandarinka [93]

Answer:

truck 1 has the most velocity

Explanation:

Because it weights less which means it faster and yea

3 0

3 years ago

the average power of the Sun is 3.79x1026 Watts, answer the following questions: 13. What is the average intensity of light at E

Lemur [1.5K]

Explanation:

Given that,

Average power of sun $P=3.79\times10^{26}\ Watt$

We need to calculate the intensity of light at Earth's position

Using formula of intensity

$I=\dfrac{P_{avg}}{4\pi r^2}$

Where, I = intensity

P = power

Put the value into the formula

$I=\dfrac{3.79\times10^{26}}{4\pi\times(1.496\times10^{11})^2}$

$I=1347.616\ W/m^2$

So, The intensity is 1347.616 W/m².

(A). We need to calculate the pressure on a solar sail due to the light of the sun if it's fully reflective

Using formula for fully reflective

$P = \dfrac{2I}{c}$

Put the value into the formula

$P=\dfrac{2\times1347.616}{3\times10^{8}}$

$P=8.984\times10^{-6}\ N/m$

(B). We need to calculate the pressure on a solar sail due to the light of the sun if it's fully reflective

Using formula for fully absorptive

$P=\dfrac{I}{c}$

$P=\dfrac{1347.616}{3\times10^{8}}$

$P=4.492\times10^{-6}\ N/m$

Hence, This is the required solution.

6 0

3 years ago

You place the spring vertically with one end on the floor. You then lay a 1.60 kg book on top of the spring and release the book

malfutka [58]

Answer:

Compression in the spring, x = 3.7 cm

Explanation:

It is given that,

Mass of the book, m = 1.6 kg

It can be assumed the spring constant of the spring is, k = 840 N/m

As the book moves down, the change in potential energy of the book is converted to spring potential energy of compression. The mathematical expression is as follows :

$\dfrac{1}{2}kx^2=mgx$

$x=\dfrac{2mg}{k}$

$x=\dfrac{2\times 1.6\ kg\times 9.8\ m/s^2}{840\ N/m}$

x = 0.037 meters

x = 3.7 cm

So, the spring is compressed to a distance of 3.7 cm. Hence, this is the required solution.

4 0

3 years ago

If you increase the mass of an object and want to move an object a specific distance, what do you need to do

Alexxandr [17]

If you increase the mass of an object and want to move an object a specific distance, then you need to do extra work than the earlier

The total amount of energy transferred when a force is applied to move an object through some distance

Work Done = Force * Displacement

For example, let us suppose a force of 10 N is used to displace an object by a displacement of 5 m then the work done on the object can be calculated by the above-mentioned formula

work done = 10 N ×5 m

=50 N m

Thus, when an object's mass is increased and it is desired to move it a certain distance, more work must be done than previously.

Learn more about work done from here

brainly.com/question/13662169

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3 0

2 years ago

How do Air molecules enable sound to travel from a radios speaker to your ears?

MatroZZZ [7]

The radio frequencies push one air molecule that then bumps into a different air molecule.....which then hits another and another causing a line of crashing molecules that lead inside your ear and hits your ear drum causing it to vibrate which causes the sounds.

6 0

3 years ago

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