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Mumz [18]
3 years ago
6

A coordinate grid is shown below: A coordinate grid from negative 2 to 0 to positive 2 is drawn. There are three grid lines betw

een a whole unit on the grid. Part A: Which point represents the origin? (2 points) Part B: Point (-1, 1) is reflected across the y-axis. Give the coordinates of the reflected point and explain how you know. (4 points)
Mathematics
1 answer:
Anastasy [175]3 years ago
3 0

Answer:

Part A: 0

Part B: (-1,-1) since point (-1,1) is located in quadrent four when it is reflected over the y axis the second point would be located in quadrent three and the x and y would both be negative.

Step-by-step explanation:

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jok3333 [9.3K]

Answer:

thank you ^-^

Step-by-step explanation:

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Write the equation of each line in slope intercept form (If possible please show work)
kow [346]

Answer:

y = -2/3x-9

Step-by-step explanation:

The slope intercept form of a line is

y = mx+b where m is the slope and b is the y intercept

y = -2/3x+b

We have a point we can substitute into the line

-5 = -2/3(-6)+b

Subtract 4 from each side

-5-4 =4+b-4

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y = -2/3x-9

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3 years ago
i have to comapre numbers in comaprison problems, and im having trouble understanding the process on how to solve. can you guys
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Give me a question i can answer. i might could help.
3 0
3 years ago
Solve 11b^2-9=-68 using the square root method
Vladimir79 [104]

Answer:

b=i*\sqrt{\frac{59}{11} } or -i*\sqrt{\frac{59}{11} }

Step-by-step explanation:

11b^2-9=-68

11b^2=-59

b^2=-59/11

b=i*\sqrt{\frac{59}{11} } or -i*\sqrt{\frac{59}{11} }

"i" in this case is an imaginary number, equal to \sqrt{-1\\}

if you haven't learned about these yet, something is wrong with the question

3 0
3 years ago
Find the missing side (X) round to the nearest hundredth
nata0808 [166]

Answer:

\displaystyle 18,28 ≈ x

Step-by-step explanation:

\displaystyle \frac{x}{11} = csc\:37 \hookrightarrow 11csc\:37 = x \hookrightarrow 18,278041552... = x \\ \\ 18,28 \approx x

<em>OR</em>

\displaystyle \frac{11}{x} = sin\:37 \hookrightarrow xsin\:37 = 11 \hookrightarrow \frac{11}{sin\:37} = x \hookrightarrow 18,278041552... = x \\ \\ 18,28 \approx x

Information on trigonometric ratios

\displaystyle \frac{OPPOCITE}{HYPOTENUSE} = sin\:θ \\ \frac{ADJACENT}{HYPOTENUSE} = cos\:θ \\ \frac{OPPOCITE}{ADJACENT} = tan\:θ \\ \frac{HYPOTENUSE}{ADJACENT} = sec\:θ \\ \frac{HYPOTENUSE}{OPPOCITE} = csc\:θ \\ \frac{ADJACENT}{OPPOCITE} = cot\:θ

I am joyous to assist you at any time.

7 0
2 years ago
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