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3 years ago

( -6)^0 solve this problem

Mathematics

2 answers:

Elodia [21]3 years ago

8 0

Answer:

Anything raise to 0 is 1

so (-6)^0=1

Katyanochek1 [597]3 years ago

4 0

Answer:

Step-by-step explanation:

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3 years ago

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Help for question 1 and 2

AnnyKZ [126]

Answer:

(1). $5^{4}$ × $13^{7}$ ; (2). 3 - 5x

Step-by-step explanation:

1). [( - 5 )³ · ( - 5 )] ( $13^{-2}$ · $13^{9}$ ) = $(-5)^{3+1}$ × $(13)^{-2+9}$ = $(-5)^{4}$ × $13^{7}$ = $5^{4}$ × $13^{7}$

2). - 25x² ÷ 5x + 15x ÷ 5x = 3 - 5x

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2 years ago

HELP PLEASE WILL MARK BRAINLIEST!!

Arte-miy333 [17]

Answer:

Answer is option d)346.4 ft

Step-by-step explanation:

$from \: the \: figure \\ AB = 300 \: ft \: \: \: angle \: C = 60 \:( theta)\: degress \\ in \: triangle \: ABC \: using \: tan \: theta\\ \tan(60) = \frac{opposite \: side}{adjacent \: side} \\ \tan(60) = \frac{300}{BC} \\ \sqrt{3} = \frac{300}{BC} \\ BC = \frac{300}{ \sqrt{3} } \\ BC = 100 \sqrt{3} ft \\ then \: in \: triangle \: ABD \: using \: tan \: theta \\ angle \: D = 30 \: degrees \: (theta) \\ \tan(30 ) =\frac{opposite \: side}{adjacent \: side} \\ \tan(30) = \frac{300}{BD} \\ \frac{1}{ \sqrt{ 3} } = \frac{300}{BD} \\ BD = 300 \sqrt{3} \\ CD = BD - BC \\ = 300 \sqrt{3 } - 100 \sqrt{3} \\ = (300 - 100) \sqrt{3} \\ = 200 \sqrt{3 } \\ = 200 \times 1.732 \\ = 346.4 \: ft$

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3 years ago

Can someone help me with this question "Given the triangle below, what is m (angle) < B, rounded to the nearest tenth?

JulsSmile [24]

The answer
the sum of the angles in a triangle is always 180°
m < B + m < A + m < C = 180°,
let's find m < B,
by applying sinus rule
14/sinB=10/sinC, so sinB= 10xsinB = 14 x sinC and therefore,
sinB=( 14/10 )sinC =7/2 sin 36° =0.82, so arcsinB=55.08°
the answer is C 55.4°

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3 years ago

What direction for negative and positive go in

skad [1K]

Answer:

negative=left positive=right

Step-by-step explanation:

negatives are less than positives

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3 years ago

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