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Cloud [144]
4 years ago
5

What is x in 4x+5=72? PLEASE ANSWER YOU WILL BE THE NEXT BRAINLIEST!!!!!!!!!!!!

Mathematics
1 answer:
Artist 52 [7]4 years ago
3 0
Hi there!

The answer to this problem is 16.75

Check your work by:

4 • 16.75 + 5 = 72

How to Answer this Problem:

You might be interested in
What value of x satfies the equation 5/6(3/8-x)=16
julsineya [31]
5/6 x 3/8 = 5/16 
5/16 - 5/6x = 16 
-5/6x=251/16
x= -753/40
5 0
3 years ago
Solve the systems of equation by graphing (Picture provided)
padilas [110]

Answer:

The option d

Step-by-step explanation:

find the intersection with x and y

https://tex.z-dn.net/?f=x%3D0%0A

https://tex.z-dn.net/?f=0%2By%3D-9%20%5Clongrightarrow%20y%3D-9%0A

and https://tex.z-dn.net/?f=y%3D0%0A

https://tex.z-dn.net/?f=x%2B0%3D-9

we get the coordinates

https://tex.z-dn.net/?f=(0%2C-9)%2C%20(-9%2C0)

and the same process for another equation

https://tex.z-dn.net/?f=4*(0)%2By%3D-19%20%5Clongrightarrow%20y%3D-19%5C%5C%0A4*x%2B0%3D-19%20%5Clongrightarrow%20x%3D%5Cfrac%7B-19%7D%7B4%7D%20%5C%5C%5C%5C%0A(0%2C-19)%2C%20(%5Cfrac%7B-19%7D%7B4%7D%2C0)%20

and these coordinates are those expressed in the d graph

3 0
3 years ago
Please any math experts help thanks you
timofeeve [1]

Answer:

\frac{p^2-25}{p^2-10p+25}

We can factorise the numerator with the difference of squares formula:x^2-y^2=(x+y)(x-y)

-----------------------------

\frac{p^2-5^2}{p^2-10p+25} =\frac{(p+5)(p-5)}{p^2-10p+25}

Now we can factorise the denominator:

\frac{(p+5)(p-5)}{p^2-10p+25} =\frac{(p+5)(p-5)}{(p-5)^2}

\frac{(p+5)(p-5)}{(p-5)^2} =\frac{(p+5)(p-5)}{(p-5)(p-5)}

Cancel out the common factor of (p-5):

\frac{(p+5)(p-5)}{(p-5)(p-5)} =\frac{(p+5)}{(p-5)}

7 0
3 years ago
Answer please I’m dying from math
charle [14.2K]

Answer:

\huge\boxed{\text{D)} \  15x^4 + 2x^3 - 8x^2 - 22x - 15}

Step-by-step explanation:

We can solve this multiplication of polynomials by understanding how to multiply these large terms.

To multiply two polynomials together, we must multiply each term by each term in the other polynomial. Each term should be multiplied by another one until it's multiplied by all of the terms in the other expression.

  • <em>We can do this by focusing on one term in the first polynomial and multiplying it by </em><em>all the terms</em><em> in the second polynomial. We'd then repeat this for the remaining terms in the second polynomial.</em>

Let's first start by multiplying the first term of the first polynomial, 3x^2, by all of the terms in the second polynomial. (5x^2+4x+5)

  • 3x^2 \cdot  5x^2 = 15x^4
  • 3x^2 \cdot 4x = 12x^3
  • 3x^2 \cdot 5 = 15x^2

Now, we can add up all these expressions to get the first part of our polynomial. Ordering by exponent, our expression is now

  • \displaystyle 15x^4 + 12x^3 + 15x^2

Now let's do the same with the second term (-2x) and the third term (-3).

  • -2x \cdot 5x^2 = -10x^3  
  • -2x \cdot 4x = -8x^2
  • -2x \cdot 5 = -10x
  • Adding on to our original expression: \displaystyle 15x^4 + 12x^3 - 10x^3 + 15x^2 - 8x^2 - 10x

  • -3 \cdot 5x^2 = -15x^2
  • -3 \cdot 4x = -12x
  • -3 \cdot 5 = -15
  • Adding on to our original expression: \displaystyle 15x^4 + 12x^3 - 10x^3 + 15x^2 - 8x^2 - 15x^2 - 10x - 12x - 15

Phew, that's one big polynomial! We can simplify it by combining like terms. We can combine terms that share the same exponent and combine them via their coefficients.

  • 12x^3 - 10x^3 = 2x^3
  • 15x^2 - 8x^2 - 15x^2 = -8x^2
  • -10x - 12x = -22x

This simplifies our expression down to 15x^4 + 2x^3 - 8x^2 - 22x - 15.

Hope this helped!

7 0
3 years ago
Read 2 more answers
Write the following quotient in the form a+bi.<br> -7i/2-7i
Helga [31]

Answer:

\large\boxed{\dfrac{49}{53}-\dfrac{14}{53}i}

Step-by-step explanation:

\text{Use}\\\\i=\sqrt{-1}\to i^2=-1\\\\(a-b)(a+b)=a^2-b^2\to(a-bi)(a+bi)=a^2+b^2\\\\\text{distributive property}\ a(b+c)=ab+ac\\---------------------\\\\\dfrac{-7i}{2-7i}=\dfrac{-7i}{2-7i}\cdot\dfrac{2+7i}{2+7i}=\dfrac{-7i(2+7i)}{2^2+7^2}=\dfrac{(-7i)(2)+(-7i)(7i)}{4+49}\\\\=\dfrac{-14i-49i^2}{53}=\dfrac{-14i-49(-1)}{53}=\dfrac{-14i+49}{53}\\\\=\dfrac{49}{53}-\dfrac{14}{53}i

8 0
3 years ago
Read 2 more answers
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