Answer:
11
Step-by-step explanation:
First subtract 
19-8= Z
So solution would be
Z=11
 
        
                    
             
        
        
        
Answer:
t≈8.0927
Step-by-step explanation:
h(t) = -16t^2 + 128t +12
We want to find when h(t) is zero ( or when it hits the ground)
0 =  -16t^2 + 128t +12
Completing the square
Subtract 12 from each side
-12  =  -16t^2 + 128t 
Divide each side by -16
-12/-16  =  -16/-16t^2 + 128/-16t
3/4 = t^2 -8t
Take the coefficient of t and divide it by 8
-8/2 = -4
Then square it
(-4) ^2 = 16
Add 16 to each side
16+3/4 = t^2 -8t+16
64/4 + 3/4= (t-4)^2
67/4 = (t-4)^2
Take the square root of each side
±sqrt(67/4) =sqrt( (t-4)^2)
±1/2sqrt(67) = (t-4)
Add 4 to each side
4 ±1/2sqrt(67) = t
The approximate values for t are
t≈-0.092676
t≈8.0927
The first is before the rocket is launched so the only valid answer is the second one
 
        
                    
             
        
        
        
7 + 3.(2 - 3x) = 67
3 brackets are distributed
7+6-9x = 67
13-9x = 67
-9x = 67
x = 67/-9
        
             
        
        
        
Answer:
C
You have to check which of numbers is the lowest.
Cheers :D