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Bumek [7]
4 years ago
6

Elements with low specific heat values have which characteristic?

Physics
2 answers:
Diano4ka-milaya [45]4 years ago
7 0
The elements which have a lower number of atoms per gram and therefore, the absorbance of heat is not much, therefore, they have low specific heat values. These elements are mostly the higher elements. Th more are the numbers of the atoms present in them, more is the energy absorbed by them, and higher is the specific heat energy. 
Lapatulllka [165]4 years ago
7 0

Answer: Option (d) is the correct answer.

Explanation:

Specific heat is defined as the amount of heat necessary for per unit mass to raise the temperature by one degree Celsius.

The formula to calculate specific heat is as follows.

                 Q = m C \Delta T

where,    Q = heat added

               m = mass of substance

               C = specific heat

        \Delta T = change in temperature

Therefore, we can conclude that elements with low specific heat values have low number of atoms per unit gram.

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A large truck and a compct car are both driving down the
koban [17]

Answer:

Explanation:

The friction force acting on the body depends on the mass of the body, here the mas of truck is very large as compared  to the car, so the friction force acting on the truck is large then the car. So, the amount of heat generated by the truck is more than the car and the truck overheated more.

7 0
3 years ago
Un puente(construido de acero) que conduce hacia una bahía mide 1.30X10-3m entre sus torres de apoyo. ¿Cuánto se dilata el puent
JulsSmile [24]

Answer:

ΔL = 0.429 m

Explanation:

The expression for linear thermal expansion is

         ΔL = α L₀ ΔT

the coefficient of linear expansion of steel is 11 10⁻⁶ ºC⁻¹

the initial length of the bridge is L₀ = 1.30 10³ m and the temperature variation is ΔT = 30 ºC

calculate  

        ΔL = 11 10⁻⁶  1.30 10³  30

        ΔL = 4.29 10⁻¹ m

        ΔL = 0.429 m

8 0
3 years ago
What is the scientific definition of tracked?
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3 years ago
Can you help me? it's an emergency
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3 years ago
A flat loop of wire consisting of a single turn of cross-sectional area 8.20 cm2 is perpendicular to a magnetic field that incre
olga nikolaevna [1]

Answer:

The  induced current is I  =  6.25*10^{-4} \  A

Explanation:

From the question we are told that  

    The number of turns is  N  =  1

     The  cross-sectional area is  A  =  8.20 cm^2  =  8.20 * 10^{-4} \ m^2

    The  initial magnetic field is  B_i  =  0.500 \ T

     The  magnetic field at time =  1.02 s  is  B_t =  2.60 \ T

     The  resistance is  R  = 2.70\  \Omega

The  induced emf is mathematically represented as

       \epsilon  = - N  *   \frac{ d\phi }{dt}

The  negative sign tells us that the induced emf is moving opposite to the change in magnetic flux

      Here  d\phi is the change in magnetic flux which is mathematically represented as

        d \phi  =  dB  *  A

Where  dB  is the change in magnetic field which is mathematically represented as

        dB  =  B_t  - B_i

substituting values

        dB  =   2.60 -  0.500

        dB  =   2.1 \ T

Thus  

      d \phi  =  2.1 * 8.20 *10^{-4}

     d \phi  = 1.722*10^{-3} \ weber

So  

     |\epsilon|  = 1   *   \frac{ 1.722*10^{-3}}{1.02}

     |\epsilon|  = 1.69 *10^{-3} \  V

The  induced current i mathematically represented as

      I  =  \frac{\epsilon}{ R }

  substituting values

       I  =  \frac{1.69*10^{-3}}{ 2.70 }

       I  =  6.25*10^{-4} \  A

7 0
4 years ago
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