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4 years ago

Elements with low specific heat values have which characteristic?

2 answers:

7 0

The elements which have a lower number of atoms per gram and therefore, the absorbance of heat is not much, therefore, they have low specific heat values. These elements are mostly the higher elements. Th more are the numbers of the atoms present in them, more is the energy absorbed by them, and higher is the specific heat energy.

Lapatulllka [165]4 years ago

7 0

Answer: Option (d) is the correct answer.

Explanation:

Specific heat is defined as the amount of heat necessary for per unit mass to raise the temperature by one degree Celsius.

The formula to calculate specific heat is as follows.

$Q = m C \Delta T$

where, Q = heat added

m = mass of substance

C = specific heat

$\Delta T$ = change in temperature

Therefore, we can conclude that elements with low specific heat values have low number of atoms per unit gram.

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car rides on four wheels that are connected to the body of the car by spring assemblies that let the wheels move up and down ove

Tomtit [17]

Answer:

78.4 KN/m

Explanation:

Given

mass of person 'm' =80 kg

car dips about i.e spring stretched 'x'= 1 cm => 0.01m

acceleration due to gravity 'g'= 9.8 m/s^2

as we know that,in order to find approximate spring constant we use Hooke's Law i.e F=kx

where,

F = the force needed

x= distance the spring is stretched or compressed beyond its natural length

k= constant of proportionality called the spring constant.

F=kx ---> (since f=mg)

mg=kx

k=(mg)/x

k=(80 x 9.8)/ 0.01

k=78.4x $10^3$

k=78.4 KN/m

3 0

3 years ago

Read 2 more answers

A railroad track and a road cross at right angles. An observer stands on the road and watches an eastbound train traveling at 60

mamaluj [8]

Answer:

After 4 s of passing through the intersection, the train travels with 57.6 m/s

Solution:

As per the question:

Suppose the distance to the south of the crossing watching the east bound train be x = 70 m

Also, the east bound travels as a function of time and can be given as:

y(t) = 60t

Now,

To calculate the speed, z(t) of the train as it passes through the intersection:

Since, the road cross at right angles, thus by Pythagoras theorem:

$z(t) = \sqrt{x^{2} + y(t)^{2}}$

$z(t) = \sqrt{70^{2} + 60t^{2}}$

Now, differentiate the above eqn w.r.t 't':

$\frac{dz(t)}{dt} = \frac{1}{2}.\frac{1}{sqrt{3600t^{2} + 4900}}\times 2t\times 3600$

$\frac{dz(t)}{dt} = \frac{1}{sqrt{3600t^{2} + 4900}}\times 3600t$

For t = 4 s:

$\frac{dz(4)}{dt} = \frac{1}{sqrt{3600\times 4^{2} + 4900}}\times 3600\times 4 = 57.6\ m/s$

4 0

3 years ago

A dielectric material such as paper is inserted between the plates of a capacitor as the capacitor holds a fixed charge on its p

Vikki [24]

Answer:

Introducing a dielectric into a capacitor decreases the electric field, which decreases the voltage, which increases the capacitance.

Explanation:

A dielectric (or dielectric material) is an electrical insulator that can be polarized by an applied electric field. When a dielectric material is placed in an electric field, electric charges do not flow through the material as they do in an electrical conductor but only slightly shift from their average equilibrium positions causing dielectric polarization

Types of dielectric material

Ceramic, Mica paper glass

7 0

3 years ago

What is the work of a 520n student walking a distance of 3 m

Wewaii [24]

Answer:

W=1560 Joules

Explanation:

Use W=fd

so, W=520N(3m)= 1560J

8 0

3 years ago

A coin is placed on a vinyl stereo record that is making 33 1/3 revolutions per minute on a turntable. (a) In what direction is

mamaluj [8]

Answer: a) The acceletarion is directed to the center on the turntable. b) 5 cm; ac= 0.59 m/s^2; 10 cm, ac=1.20 m/s^2; 14 cm, ac=1.66 m/s^2

Explanation: In order to explain this problem we have to consider teh expression of the centripetal accelartion for a circular movement, which is given by:

ac=ω^2*r where ω and r are the angular speed and teh radios of the circular movement.

w=2*π*f

We know that the turntable is set to 33 1/3 rev/m so

the frequency 33.33/60=0.55 Hz

then w=2*π*0.55=3.45 rad/s

Finally the centripetal acceleration at differents radii results equal:

r= 0.05 m ac=3.45^2*0.05=0.50 m/s^2

r=0.1 ac=3.45^2*0.1=1.20 m/s^2

r=0.14 ac=3.45^2*0.14=1.66 m/s^2

4 0

3 years ago