Well, if we've been paying attention in class, we already KNOW that the electrostatic force changes as the inverse square of the distance, and the top graph is conveniently labeled "Electrostatic Force".
But if we didn't already know that, we'd have to examine the graphs, and find the one where 'y' changes like 1/x² .
The top graph does that. After 1 unit of time, the force is 350. Double the time to 2 units, and the force should drop to 1/4 of 350 ... sure enough, it's a little less than 90. Double the time again, to 4 units, and it should drop to 1/4 of a little less than 90 ... by golly, it's down below 30.
The first graph is what an inverse square looks like. Now that you've worked out this graph, you'll know an inverse square relationship whenever you see it.
Answer:
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Explanation:
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Change in electric potential energy: 121.5 nJ
Explanation:
For a charged particle moving in an electric field, the change in electric potential energy of the particle is given by

where:
q is the charge of the particle
is the potential difference between the initial and final position of the particle
For the point charge in this problem, we have:
is the charge
is the potential difference
Therefore, the change in electric potential energy is

Learn more about electric fields:
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Force between two charges =
( 1/4πε₀ ) · (Charge #1) · (Charge #2) / (Distance between them)²
in the direction away from each other.
In other words, if the force is positive, the charges are repelling.
If the force is negative, the charges are attracting.
Question: A loader sack of total mass
is l000 grams falls down from
the floor of a lorry 200 cm high
Calculate the workdone by the
gravity of the load.
Answer:
19.6 Joules
Explanation:
Applying
W = mgh........................ Equation 1
Where W = Workdone by gravity on the load, m = mass of the loader sack, h = height, g = acceleration due to gravity
From the question,
Given: m = 1000 grams = (1000/1000) kilogram = 1 kg, h = 200 cm = 2 m
Constant: g = 9.8 m/s²
Substitute these values into equation 1
W = (1×2×9.8)
W = 19.6 Joules
Hence the work done by gravity on the load is 19.6 Joules