Answer:
The average acceleration during the 6.0 s interval was -27 m/s².
Explanation:
Hi there!
The average acceleration is defined as the change in velocity over time:
a = Δv/t
Where:
a = acceleration.
Δv = change in velocity = final velocity - initial velocity
t = elapsed time
The change in velocity will be:
Δv = final velocity - initial velocity
Δv = -74 m/s - 87 m/s = -161 m/s
(notice the negative sign of the velocity that is in opposite direction to the direction considered positive)
Then the average acceleration will be:
a = Δv/t
a = -161 m/s / 6.0 s
a = -27 m/s²
The average acceleration during the 6.0 s interval was -27 m/s².
<span>D. measuring radioactive decay of element isotopes </span>
Answer:
vB = 8.57[m/s]
Explanation:
Since there is no external force that generates momentum, the amount of momentum is conserved so you will have the following equation
![m_{A}*v_{A}=m_{B}*v_{B}\\Where:\\m_{A}= 90[kg]\\v_{A}=10[m/s]\\m_{B}=105[kg]\\\\Therefore:\\\\v_{B}=\frac{m_{A}*v_{A}}{m_{B}}\\ v_{B}=\frac{90*10}{105}\\v_{B}=8.57[m/s]](https://tex.z-dn.net/?f=m_%7BA%7D%2Av_%7BA%7D%3Dm_%7BB%7D%2Av_%7BB%7D%5C%5CWhere%3A%5C%5Cm_%7BA%7D%3D%2090%5Bkg%5D%5C%5Cv_%7BA%7D%3D10%5Bm%2Fs%5D%5C%5Cm_%7BB%7D%3D105%5Bkg%5D%5C%5C%5C%5CTherefore%3A%5C%5C%5C%5Cv_%7BB%7D%3D%5Cfrac%7Bm_%7BA%7D%2Av_%7BA%7D%7D%7Bm_%7BB%7D%7D%5C%5C%20v_%7BB%7D%3D%5Cfrac%7B90%2A10%7D%7B105%7D%5C%5Cv_%7BB%7D%3D8.57%5Bm%2Fs%5D)
Answer:
Angle θ = 30.82°
Explanation:
From Malus’s law, since the intensity of a wave is proportional to its amplitude squared, the intensity I of the transmitted wave is related to the incident wave by; I = I_o cos²θ
where;
I_o is the intensity of the polarized wave before passing through the filter.
In this question,
I is 0.708 W/m²
While I_o is 0.960 W/m²
Thus, plugging in these values into the equation, we have;
0.708 W/m² = 0.960 W/m² •cos²θ
Thus, cos²θ = 0.708 W/m²/0.960 W/m²
cos²θ = 0.7375
Cos θ = √0.7375
Cos θ = 0.8588
θ = Cos^(-1)0.8588
θ = 30.82°
