Answer:
a) I = 2279.5 N s
, b) F = 3.80 10⁵ N, c) I = 3125.5 N s and d) F = 5.21 10⁵ N
Explanation:
The impulse is equal to the variation in the amount of movement.
I =∫ F dt = Δp
I = m
- m v₀
Let's calculate the final speed using kinematics, as the cable breaks the initial speed is zero
² = V₀² - 2g y
² = 0 - 2 9.8 30.0
= √588
= 24.25 m/s
a) We calculate the impulse
I = 94 24.25 - 0
I = 2279.5 N s
b) Let's join the other expression of the impulse to calculate the average force
I = F t
F = I / t
F = 2279.5 / 6 10⁻³
F = 3.80 10⁵ N
just before the crash the passenger jumps up with v = 8 m / s, let's take the moments of interest just when the elevator arrives with a speed of 24.25m/s down and as an end point the jump up to vf = 8 m / n
c) I = m
- m v₀
I = 94 8 - 94 (-24.25)
I = 3125.5 N s
d) F = I / t
F = 3125.5 / 6 10⁻³
F = 5.21 10⁵ N
as it is given that it covers a total distance 1 * 10^2 m
total time taken by it = 13.6 s
now the average speed is given as ratio of total distance and total time



so the average speed will be 7.35 m/s
now if it starts from rest and achieve the final speed as 7.35 m/s
now we can use kinematics



so its acceleration will be 3.68 m/s^2
Answer:
A. Its unique strength allows predetermined engineering stresses to be placed in members to counteract stresses that occur when the unit is subjected to service loads
Explanation:
Prestressed concrete is a structural material that allows for predetermined, engineering stresses to be placed in members to counteract the stresses that occur when they are subject to loading.
It combines the high strength compressive properties of concrete with the high tensile strength of steel.
‘Building Construction Handbook’ (6th ed.), CHUDLEY, R., GREENO, R., Butterworth-Heinemann (2007)
Then the correct answer is:
A. Its unique strength allows predetermined engineering stresses to be placed in members to counteract stresses that occur when the unit is subjected to service loads
I think it is (c) but I’m not 100% sure
Answer:2
Explanation:
Given
Velocity of bicycle is 5 m/s towards north
radius of rim 
mass of rim 
Angular momentum 


direction of Angular momentum will be towards west