1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
lapo4ka [179]
3 years ago
13

A truck traveling at a constant speed of 28 m/s passes a more slowly moving car. The instant the truck passes the car, the car b

egins to accelerate at a constant rate of 1.2 m/s^2 and passes the truck 545 m farther down the road. What was the speed of the car (in meters/second) when it was first passed by the truck?
Physics
1 answer:
choli [55]3 years ago
5 0

Answer:

the velocity of car when it passes the truck is u = 16.33 m/s

Explanation:

given,

constant speed of truck  = 28 m/s

acceleration of car = 1.2 m/s²

passes the truck in 545 m

speed of the car when it just pass the truck = ?

time taken by the truck to travel 545 m

              time =\dfrac{distance}{speed}

              time =\dfrac{545}{28}

              time =19.46 s

velocity of the car when it crosses the truck

S = ut + \dfrac{1}{2}at^2

545= u\times 19.46 + \dfrac{1}{2} \times 1.2 \times 19.46^2

u = 16.33 m/s

the velocity of car when it passes the truck is u = 16.33 m/s

You might be interested in
The official web site of the Nobel Prize explains that Marie Curie’s chemistry prize was partly for her discovery that the radio
anastassius [24]

The official web site of the Nobel Prize explains that Marie Curie’s chemistry prize was partly for her discovery that the radioactivity of a substance is unaffected when it undergoes a chemical reaction. The discovery implied was that, Radioactivity involves Radioactivity involves only neutrons.

Explanation:

  • The official web site of the Nobel Prize explains that Marie Curie’s chemistry prize was partly for her discovery that the radioactivity of a substance is unaffected when it undergoes a chemical reaction. The discovery implied was that, Radioactivity involves only neutrons.
  • Marie Curie studied about the radiation of all compounds containing the known radioactive elements, including uranium and thorium, which she later discovered that they were radioactive.
  • she discovered the following results,
  • the exact measurement of the strength of the radiation from uranium;
  • the intensity of the radiation was found to be proportional to the amount of uranium or thorium in the compound .
  • the ability to emit radiation is not dependent on the arrangement of the atoms in a molecule;
  • it must be linked to the interior of the atom itself which is a revolutionary discovery.

8 0
3 years ago
What are the names of the 4 types of fronts? How are they created?
jeka57 [31]

Answer:

Stationary Front, warm front, cold front, Occluded Front.

Explanation:

Stationary Front. When the surface position of a front does not change (when two air masses are unable to push against each other; a draw), a stationary front is formed.

cold front is the leading edge of a cooler mass of air at ground level that replaces a warmer mass of air and lies within a pronounced surface trough of low pressure. It often forms behind an extratropical cyclone (to the west in the Northern Hemisphere, to the east in the Southern), at the leading edge of its cold air advection pattern—known as the cyclone's dry "conveyor belt" flow. Temperature differences across the boundary can exceed 30 °C (86 °F) from one side to the other. When enough moisture is present, rain can occur along the boundary. If there is significant instability along the boundary, a narrow line of thunderstorms can form along the frontal zone. If instability is weak, a broad shield of rain can move in behind the front, and evaporative cooling of the rain can increase the temperature difference across the front. Cold fronts are stronger in the fall and spring transition seasons and weakest during the summer.

A warm front is a density discontinuity located at the leading edge of a homogeneous warm air mass, and is typically located on the equator-facing edge of an isotherm gradient. Warm fronts lie within broader troughs of low pressure than cold fronts, and move more slowly than the cold fronts which usually follow because cold air is denser and less easy to remove from the Earth's surface. This also forces temperature differences across warm fronts to be broader in scale. Clouds ahead of the warm front are mostly stratiform, and rainfall gradually increases as the front approaches. Fog can also occur preceding a warm frontal passage. Clearing and warming is usually rapid after frontal passage. If the warm air mass is unstable, thunderstorms may be embedded among the stratiform clouds ahead of the front, and after frontal passage thundershowers may continue. On weather maps, the surface location of a warm front is marked with a red line of semicircles pointing in the direction of travel.

In meteorology, an occluded front is a weather front formed during the process of cyclogenesis. The classical view of an occluded front is that they are formed when a cold front overtakes a warm front, such that the warm air is separated (occluded) from the cyclone center at the surface. The point where the warm front becomes the occluded front is called the triple point; a new area of low-pressure that develops at this point is called a triple-point low. A more modern view of the formation process suggests that occluded fronts form directly during the wrap-up of the baroclinic zone during cyclogenesis, and then lengthen due to flow deformation and rotation around the cyclone.

3 0
3 years ago
Read 2 more answers
It is easier to lift the same load by using three pulley system than by using two-pulley system. why give reason.​
tresset_1 [31]
<h2>QUESTION:- It is easier to lift the same load by using three pulley system than by using two-pulley system.</h2>

<h2>ANSWER:- IN CASE OF IDEAL PULLEY SYSTEM</h2>

<h2>REASON:- </h2>

Logic behind is lies behind the mechanical advantage of the provided bt the Pulley system.

as if we calculate the mechanical advantage of the 2 Pulley system we will have the value 2

And if we will calculate the mechanical advantage of the 3 pulley system then we will get the value of 3

so due to extra mechanical advantage we feel it easy to move with 3 pulley system then 2 Pulley system

\red \star{Thanks \:  And  \: Brainlist}  \blue\star \\  \green\star  If \:  U  \: Liked \:  My  \: Answer \purple \star

7 0
3 years ago
A cross-country skier slides horizontally along the snow and comes to rest after sliding a distance of 11 m. If the coefficient
Basile [38]

Answer:

v_o = 4.54 m/s  

Explanation:

<u>Knowns  </u>

From equation, the work done on an object by a constant force F is given by:  

W = (F cos Ф)S                                   (1)  

Where S is the displacement and Ф is the angle between the force and the displacement.  

From equation, the kinetic energy of an object of mass m moving with velocity v is given by:  

K.E=1/2m*v^2                                       (2)

From The work- energy theorem , the net work done W on an object equals the difference between the initial and the find kinetic energy of that object:  

W = K.E_f-K.E_o                                 (3)

<u>Given </u>

The displacement that the sled undergoes before coming to rest is s = 11.0 m and the coefficient of the kinetic friction between the sled and the snow is μ_k = 0.020  

<u>Calculations</u>

We know that the kinetic friction force is given by:

f_k=μ_k*N

And we can get the normal force N by applying Newton's second law to the sled along the vertical direction, where there is no acceleration along this direction, so we get:  

∑F_y=N-mg

     N=mg

Thus, the kinetic friction force is:  

f_k = μ_k*N  

Since the friction force is always acting in the opposite direction to the motion, the angle between the force and the displacement is Ф = 180°.  

Now, we substitute f_k and Ф into equation (1), so we get the work done by the friction force:  

W_f=(f_k*cos(180) s

      =-μ_k*mg*s

Since the sled eventually comes to rest, K.E_f= 0 So, from equation (3), the net work done on the sled is:  

W= -K.E_o    

Since the kinetic friction force is the only force acting on the sled, so the net work on the sled is that of the kinetic friction force  

W_f= -K.E_o  

From equation (2), the work done by the friction force in terms of the initial speed is:  

W_f=-1/2m*v^2  

Now, we substitute for W_f= -μ_k*mg*s, and solving for v_o so we get:  

-μ_k*mg*s = -1/2m*v^2  

v_o = √ 2μ_kg*s

Finally, we plug our values for s and μ_k, so we get:  

v_o = √2 x (0.020) x (9.8 m/s^2) x (11.0 m) = 4.54 m/s  

v_o = 4.54 m/s  

6 0
3 years ago
Read 2 more answers
PLEASE HELP ME SOMEONE
sasho [114]
I think its B or D, most likely D.
7 0
3 years ago
Other questions:
  • What is an electric motor? Explain its operation.
    8·2 answers
  • It takes 1 minute for 45 c to pass a point in a circuit, what is the current flowing through the circuit?
    5·1 answer
  • The speed at which the package hits the ground is really fast! If a package hits the ground at such a speed, it can be crushed a
    7·1 answer
  •  explain why earths acceleration is usually very small compared to the acceleration of the object the earth interact with
    10·1 answer
  • Which chart provides the correct number of neutrons for each isotope of tin (Sn)?
    14·1 answer
  • Two resistors, A and B, are connected in a series circuit with a battery. The resistance of A is twice that of B. Which resistor
    9·1 answer
  • What is this? Plz I need help...
    5·1 answer
  • Convert .54g to dekagrams. NEED HELP!!!!!!
    8·2 answers
  • Medium frequency waves are called what
    9·1 answer
  • Hold a spoon such that the water will hit the back of the spoon. The handle of the spoon will be horizontal. Turn on the water,
    11·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!