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3 years ago

The valence electrons found in metallic bonds are different from other bonds because

Chemistry

1 answer:

4vir4ik [10]3 years ago

5 0

Answer:

The valence electrons in the metal atom in the lattice structure can delocalize and move freely. The electrons are "loosely" connected with their parent atom in the metallic bond because most metals have excess electrons in their outer orbitals above the stable configuration.

Explanation:

Says google

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Which condition must be met in order for an equation to be balanced?

olga55 [171]

Answer:

The elements in the reactants are the same as the elements in the products.

Explanation:

You can't have more or less elements or atoms, but you also can't just have the same number of atoms because then it could be different elements, which can't happen.

5 0

3 years ago

Read 2 more answers

Please help! Calculate the percent by mass of water in FeCl2 · 4H20.

Sedaia [141]

Answer:

36.23 %

Explanation:

Let's assume we have 1 mol of FeCl₂ · 4H₂O. In that case we would have:

1 mol of FeCl₂, weighing 126.75 g (that's the molar mass of FeCl₂), and

4 moles of H₂O, weighing (4 * 18 g/mol) 72 g.

Now we can calculate the percent by mass of water:

% mass = mass of water / total mass * 100%

% mass = $\frac{72}{72+126.75}$ * 100% = 36.23 %

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3 years ago

True or false: The product of a chemical reaction is always different than the original reactants.

TEA [102]

Answer:

The answer is true

Explanation:

Products in chemical reactions are rearranged during the reaction, the atoms end up in different combinations in the products. This makes the product new substances that are chemically different than the reactants

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3 years ago

Blood is forced through the body by the

belka [17]

Blood is pumped throughout the body by your heart. Your heart is the main organ responsible for blood circulation.

8 0

4 years ago

How much heat is absorbed during production of 147 g of NO by the combination of nitrogen and oxygen?

marin [14]

Answer:

$\large \boxed{\text{105 kcal}}$

Explanation:

MM: 30.01

N₂ + O₂ ⟶ 2NO; ΔH = +43 kcal/mol

m/g: 147

Treat the heat as if it were a reactant in the reaction. Then you can write

N₂ + O₂ + 43 kcal ⟶ 2NO

The conversion factor is then 43 kcal/2 mol NO.

1. Moles of NO

$\text{Moles of NO} = \text{147 g NO} \times \dfrac{\text{1 mol NO}}{\text{30.01 g NO}} = \text{4.898 mol NO}$

2. Amount of heat

$\text{Heat} = \text{4.898 mol NO } \times \dfrac{\text{43 kcal}}{\text{2 mol NO}} = \text{105 kcal}\\\\\text{The reaction absorbs $\large \boxed{\textbf{105 kcal}}$}$

7 0

3 years ago