Answer:
Alkene A is more stable than alkene B
Explanation:
Complete question:
The same alkane is obtained from the catalytic hydrogenation of both alkene A and alkene B. The heat of hydrogenation of alkene A is 29.8 kcal/mol, and the heat of hydrogenation of alkene B is 31.4 kcal/mol. Which alkene is more stable ?
Step 1: Data given
The heat of hydrogenation of alkene A is 29.8 kcal/mol
The heat of hydrogenation of alkene B is 31.4 kcal/mol
Step 2: Which alkene is more stable
The smaller the heat of hydrogenation, the more stable the alkene. This because it releases less heat, and has less energy.
29.8 < 31.4
This means alkene A has a smaller heat of hydrogenation than alkene B
Alkene A is more stable than alkene B
Answer:
This question is asking to identify the variables in the experiment
Independent variable: different salt concentration
Dependent variable: Height of plants
Control group: Plants that receive pure water
Experimental group: Plants that receive different concentration of the salt water solution
Explanation:
The independent variable is the variable that is manipulated or changed by the experimenter in order to bring about a measurable outcome. In this experiment, the independent variable is the DIFFERENT SALT CONCENTRATION the plants were exposed to.
The dependent variable is the variable that responds to the change or manipulation of the independent variable or the measured variable. In this experiment, the dependent variable is the HEIGHT OF THE PLANTS.
The experimental group refers to the group that receives the experimental treatment. The experimental group in this experiment are the PLANTS THAT RECEIVE DIFFERENT CONCENTRATION OF SALT SOLUTIONS.
The control group does not receive any experimental treatment as the independent variable is unchanged. The control group is the PLANT THAT RECEIVE PURE WATER i.e no salt solution
A. hydroxide is the answer
Answer:
V = 42.6 L
Explanation:
Given data:
Number of moles of Cl₂ = 1.9 mol
Temperature and pressure = standard
Volume occupy = ?
Solution:
The given problem will be solve by using general gas equation,
PV = nRT
P= Pressure
V = volume
n = number of moles
R = general gas constant = 0.0821 atm.L/ mol.K
T = temperature in kelvin
By putting values,
1 atm × V = 1.9 mol ×0.0821 atm.L /mol.K × 273.15 k
V = 42.6 atm.L / 1 atm
V = 42.6 L