The 2,4 and 5 positions are accessible for nitration of 1,3‑dimethylbenzene. The final product is shown in the image attached.
<h3>What is nitration?</h3>
Nitration is a type of reaction in which the nitro group (-NO2) is introduced to an aromatic ring. We have to note that in the compound 1,3‑dimethylbenzene, the 2,4 and 5 positions are accessible for nitration as shown.
Hence, the nitration of 1,3‑dimethylbenzene occurs as shown in the image attached with the compound shown being the major product.
Learn more about nitration: brainly.com/question/5346392
Answer:
pKa = - 1.36012
Explanation:
∴ Ka = [H+] [A-] / [HA]
- % dissociates (%α) = ([A-] / [A-] + [HA])×100
∴ %α = 99.1%
∴ <em>C</em> HA = 0.21 M
Mass Balance:
⇒ <em>C </em>HA = [HA] + [A-] = 0.21 M............(1)
Charge balance:
⇒ [H+] = [A-] + [OH-].....[OH-] is neglected, it come from the water
⇒ [H+] = [A-]...............(2)
(2) in (1):
⇒ [HA] = 0.21 - [H+]
replacing in %α:
∴ %α = 99.1% = ([A-]/([A-]+[HA]))×100
⇒ 0.991 = [A-] / [A-] + [HA] = [A-] / 0.21 M
⇒ [A-] = (0.21 M)*(0.991) = 0.20811 M
Replacing in Ka:
⇒ Ka = [H+]² / (0.21 - [H+])
∴ [H+] = [A-] = 0.20811 M
⇒ Ka = (0.20811)² / (0.21 - 0.20811)
⇒ Ka = 22.9152
⇒ pKa = - Log (22.9152)
⇒ pKa = - 1.3601
<h3>
Answer:</h3>
The products of the reaction are; AgCl and NaNO₃
<h3>
Explanation:</h3>
In this question we need to know what is a double displacement reaction;
- A double displacement is a type of replacement reaction in which salts or ionic compounds exchange cations and anions to form new compounds as the products.
- In this case, the complete double replacement reaction is;
AgNO₃(aq) + NaCl(aq) → AgCl(s) + NaNO₃(aq)
- The reaction is also a precipitation reaction as it forms a precipitate as one of the products that is silver chloride (AgCl).
- Therefore, the products of the reaction are; AgCl and NaNO₃
