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ohaa [14]
3 years ago
10

What is 1s2, 2s2s, 2p6, 3s2, 3p5

Chemistry
1 answer:
Sedaia [141]3 years ago
3 0
<span>1s2 2s2 2p6 3s2 3p2, P (Phosphorous)1s2 2s2 2p6 3s2 3p3,S (Sulfur)1s2 2s2 2p6 3s2 3p4,Cl (Chlorine)1s2 2s2 2p6 3s2 3p5, Ar ( Argon)1s2 2s2 2p6 3s2.</span>
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A solution with a molarity of 0.1850 contains 19.30 grams of BaCl2. What is the volume of the solution
svetlana [45]

Answer:

Volume in L = 0.50 L

Explanation:

Given data:

Molarity of solution = 0.1850 M

Mass of BaCl₂ = 19.30 g

Volume of solution = ?

Solution:

First of all we will calculate the number of moles of solute:

Number of moles = mass/molar mass

Molar mass of BaCl₂ = 208.23 g/mol

Number of moles = 19.30 g / 208.23 g/mol

Number of moles = 0.093 mol

Volume of solution:

Molarity = number of moles of solute / volume of solution in L

0.1850 M = 0.093 mol / Volume in L

Volume in L = 0.093 mol / 0.1850 M  (M= mol/L)

Volume in L = 0.50 L

4 0
3 years ago
The amazing successes of science are because scientists have followed the rules of science
Hitman42 [59]
False is the answer
3 0
3 years ago
Read 2 more answers
Part a the disproportionation of mn2+(aq) to mn(s) and mno2(s) in acid solution at 25 ∘c. calculate δg∘rxn.
ollegr [7]

Answer:

ΔG^{o} = -461198.3 J

Explanation:

Gibbs free energy is defined as the energy associated with a given chemical reaction which can be used to do work. Firstly, we need to figure out the chemical equation for the given problem. For the given problem, the chemical equation is:

Mn^{2+} _{(aq)} + 2e^{-}⇒Mn_{(s)}      E^{o} = -1.18 V

Mn^{2+} _{(aq)} + H_{2}O ⇒MnO_{2(s)} +4H^{+} + 2e^{-}E^{o} = -1.21 V

The addition of the two E^{o} gives the E_{cell} of the equation, i.e. -1.18-1.21 = -2.39 V.

Then, using the equation for ΔG^{o}, we have:

ΔG^{o} = n*F*E^{o} = 2*96485*-2.39 = -461198.3 J

4 0
4 years ago
Write the net ionic equation for this reaction occurring in water: ammonium fluoride and magnesium chloride are mixed to form ma
MAXImum [283]

Correct answer: 3. Mg^{2+}(aq) + 2 F^{-}(aq) --> MgF_{2}(s)

The given chemical reaction is between ammonium fluoride and magnesium chloride to form magnesium fluoride and ammonium chloride.

The balanced chemical equation representing the reaction will be,

2NH_{4}F (aq) + MgCl_{2}(aq) -->MgF_{2} (s) + 2NH_{4}Cl (aq)

The complete ionic equation for the reaction: All the compounds soluble in water (aqueous) will split into ions, MgF_{2} will not split into ions as it is insoluble in water.

2 NH_{4}^{+}(aq) + 2 F^{-}(aq) + Mg^{2+}(aq) + 2 Cl^{-}(aq) --> MgF_{2}(s) + 2 NH_{4}^{+}(aq) + 2 Cl^{-}(aq)

The net ionic equation will be:

Mg^{2+}(aq) + 2 F^{-}(aq) --> MgF_{2}(s)

Here the spectator ions are NH_{4}^{+} and Cl^{-}


6 0
3 years ago
An aqueous potassium iodate ( KIO3 ) solution is made by dissolving 562 562 grams of KIO 3 KIO3 in sufficient water so that the
maxonik [38]

Answer:

Molarity of KIO_{3} solution is 0.612 mol/L

Explanation:

Number of moles of a substance = (mass of substance)/(molar mass of the substance)

Molar mass of KIO_{3} = 214 g/mol

So, 562 g of KIO_{3} = \frac{562}{214} moles of KIO_{3} = 2.63 moles of KIO_{3}

Molarity of a solution = (number of moles of solute in solution)/(total volume of solution in liter)

Here solute is KIO_{3} and solvent is water

Total volume of solution is 4.30 L

So, molarity of KIO_{3} solution = \frac{2.63}{4.30}mol/L = 0.612 mol/L

3 0
3 years ago
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