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ohaa [14]
2 years ago
10

What is 1s2, 2s2s, 2p6, 3s2, 3p5

Chemistry
1 answer:
Sedaia [141]2 years ago
3 0
<span>1s2 2s2 2p6 3s2 3p2, P (Phosphorous)1s2 2s2 2p6 3s2 3p3,S (Sulfur)1s2 2s2 2p6 3s2 3p4,Cl (Chlorine)1s2 2s2 2p6 3s2 3p5, Ar ( Argon)1s2 2s2 2p6 3s2.</span>
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The best solution to the solid waste problem is to ________. the best solution to the solid waste problem is to ________. increa
yaroslaw [1]
 the answer is decade and waste

8 0
3 years ago
The Ka for formic acid (HCO2H) is 1.8 × 10-4. What is the pH of a 0.35 M aqueous solution of sodium formate (NaHCO2)?
anzhelika [568]

Answer:

9.36

Explanation:

Sodium formate is the conjugate base of formic acid.

Also,

K_a\times K_b=K_w

K_b for sodium formate is K_b=\frac {K_w}{K_a}

Given that:

K_a of formic acid = 1.8\times 10^{-4}

And, K_w=10^{-14}

So,

K_b=\frac {10^{-14}}{1.8\times 10^{-4}}

K_b=5.5556\times 10^{-11}

Concentration = 0.35 M

HCOONa    ⇒     Na⁺ +    HCOO⁻

Consider the ICE take for the formate  ion as:

                                   HCOO⁻ + H₂O   ⇄   HCOOH + OH⁻

At t=0                              0.35                            -              -

At t =equilibrium           (0.35-x)                          x           x            

The expression for dissociation constant of sodium formate is:

K_{b}=\frac {[OH^-][HCOOH]}{[HCOO^-]}

5.5556\times 10^{-11}=\frac {x^2}{0.35-x}

Solving for x, we get:

x = 0.44×10⁻⁵  M

pOH = -log[OH⁻] = -log(0.44×10⁻⁵) = 4.64

pH + pOH = 14

So,

<u>pH = 14 - 4.64 = 9.36</u>

5 0
3 years ago
Help Please!!!!!!!!!!
Shkiper50 [21]

Answer:

L/EGFOU;T4444444444444444444444czgfryewi;adkb,SJJ>RL:IAO:YHSBRAGldOUSDHRIUITUER

Explanation:

DHFUIEY7RY8EFUIDJKJEUSDYRIFU8ERJFHJSX

4 0
2 years ago
Need help !!!!! ASAP
gavmur [86]
<h2>Hello!</h2>

The answer is:

The new temperature will be equal to 4 K.

T_{2}=4K

<h2>Why?</h2>

We are given the volume, the first temperature and the new volume after the gas is compressed. To calculate the new temperature after the gas was compressed, we need to use Charles's Law.

Charles's Law establishes a relationship between the volume and the temperature at a gas while its pressure is constant.

Now, to calculate the new temperature we need to assume that the pressure is kept constant, otherwise, the problem would not have a solution.

From Charle's Law, we have:

\frac{V_{1}}{T_{1}}=\frac{V_{2}}{T_{2}}

So, we are given the following information:

V_{1}=500mL\\T_{1}=20K\\V_{2}=100mL

Then, isolating the new temperature and substituting the given information, we have:

\frac{V_{1}}{T_{1}}=\frac{V_{2}}{T_{2}}

T_{2}=\frac{T_{1}}{V_{1}}*V_{2} \\

T_{2}=\frac{20.00K}{500mL}*100mL\\

T_{2}=4K

Hence, the new temperature will be equal to 4 K.

T_{2}=4K

Have a nice day!

7 0
3 years ago
Which of the following is considered a form of technology?
anygoal [31]

Answer:

The answer is B. Hope this helps! please give me brainliest!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!! =)

8 0
3 years ago
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