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ohaa [14]
3 years ago
10

What is 1s2, 2s2s, 2p6, 3s2, 3p5

Chemistry
1 answer:
Sedaia [141]3 years ago
3 0
<span>1s2 2s2 2p6 3s2 3p2, P (Phosphorous)1s2 2s2 2p6 3s2 3p3,S (Sulfur)1s2 2s2 2p6 3s2 3p4,Cl (Chlorine)1s2 2s2 2p6 3s2 3p5, Ar ( Argon)1s2 2s2 2p6 3s2.</span>
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How many neutrons are in an atom of tin? Round your answer to the nearest whole number.
Ray Of Light [21]
There are 50 neutrons in and atom of tin.

8 0
3 years ago
Read 2 more answers
If this decay has a half life of 2.60 years, what mass of 72.5 g of sodium 22 will remain after 15.6 years
Vlad1618 [11]

Sodium-22 remain : 1.13 g

<h3>Further explanation </h3>

The atomic nucleus can experience decay into 2 particles or more due to the instability of its atomic nucleus.  

Usually, radioactive elements have an unstable atomic nucleus.  

General formulas used in decay:  

\large{\boxed{\bold{N_t=N_0(\dfrac{1}{2})^{T/t\frac{1}{2} }}}

T = duration of decay  

t 1/2 = half-life  

N₀ = the number of initial radioactive atoms  

Nt = the number of radioactive atoms left after decaying during T time  

half-life = t 1/2=2.6 years

T=15.6 years

No=72.5 g

\tt Nt=72.5.\dfrac{1}{2}^{15.6/2.6}\\\\Nt=72.5.\dfrac{1}{2}^6\\\\Nt=1.13~g

8 0
3 years ago
In the biosynthetic pathway for folic acid, the compound PABA is the normal substrate for an enzyme in the pathway. The antibiot
ValentinkaMS [17]

Answer:

Inhibitor

Explanation:

Enzyme inhibitors are compounds that can interact with the enzyme but don't trigger any biological response. This is what sulfanilamide does. When the enzyme is bound to sulfanilamide, it stops being able to bind PABA, its normal substrate, and so it cannot perform its biological action. In consequence, the entire biosynthetic pathway for folic acid is stopped.

4 0
3 years ago
Need help this question QUICK
tino4ka555 [31]
The answer is number 2
4 0
3 years ago
The enthalpy of fusion of solid n-butane is 4.66 kJ/mol. Calculate the energy required to melt 58.3 g of solid n-butane.
adelina 88 [10]

Answer : The energy required to melt 58.3 g of solid n-butane is, 4.66 kJ

Explanation :

First we have to calculate the moles of n-butane.

\text{Moles of n-butane}=\frac{\text{Mass of n-butane}}{\text{Molar mass of n-butane}}

Given:

Molar mass of n-butane = 58.12 g/mole

Mass of n-butane = 58.3 g

Now put all the given values in the above expression, we get:

\text{Moles of n-butane}=\frac{58.3g}{58.12g/mol}=1.00mol

Now we have to calculate the energy required.

Q=\frac{\Delta H}{n}

where,

Q = energy required

\Delta H = enthalpy of fusion of solid n-butane = 4.66 kJ/mol

n = moles = 1.00 mol

Now put all the given values in the above expression, we get:

Q=\frac{4.66kJ/mol}{1.00mol}=4.66kJ

Thus, the energy required to melt 58.3 g of solid n-butane is, 4.66 kJ

7 0
3 years ago
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