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sergiy2304 [10]
3 years ago
13

If a mineral has a daughter to parent ration of 3:1 (three daughter atoms for every one parent atom), how many half-lives have p

assed since the mineral formed?
Chemistry
1 answer:
kirill [66]3 years ago
4 0
The answer to this question would be: 2 half-lives

In this question, the mineral has a daughter to parent ratio of 3:1. That means, the amount of parent mass should be are 1/(3+1)= 1/4 of the total mass. For every half live, the parent mass would become 1/2. Then for 1/4, the number of half-lives should be:
1/2^x= 1/4
1/2^x= 1/2^2
x=2
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PLZZZZZZZ HELP MEEEEEE!!!!!!!!!!
nikitadnepr [17]

Answer:

Its Obviously Dinosaurs

Explanation: They died 65 million years ago

7 0
3 years ago
Element x reacts with oxygen to produce x2o3 in an experiment it is found that 1.0000 g of x produces 1.1xxx g of x2o3 what is t
8_murik_8 [283]

Since X is 1 g, therefore O must be 0.1 g. Therefore:

moles O = 0.1 g / (16 g / mol) = 0.00625 mol

 

We can see that for every 3 moles of O, there are 2 moles of X, therefore:

moles X = 0.00625 mol O (3 moles X / 2 moles O) = 0.009375 mol

 

Molar mass X = 1 g / 0.009375 mol

<span>Molar mass X = 106.67 g/mol</span>

4 0
3 years ago
The agent of mechanical weathering in which rock is worn away by the grinding action of other rock particles is call
Igoryamba

Physical weathering

3 0
3 years ago
How many neutrons does element X have if its atomic number is 30 and its mass number is 70?
Yanka [14]
The answer is 40.

We can solve this by finding out the number of protons, and neutrons. Atomic number of an element means the number of protons in that element. So, the atom has 30 protons if the atomic number is 30.

On the other hand, mass number is the total number of protons and neutrons, but not electrons, because they're too light comparing to the other 2. Therefore, we can simply solve the number of neutrons in the atom by subtracting the number of protons from the mass number. 70 - 30 = 40.

Therfore, the number of neutrons is 40.
3 0
3 years ago
Submit What is the solubility of Cd3(POA) 2 in water? (Ksp of Cd3(PO4)2 is 2.5 x 10-33) | 1 2 3 +/- . 0 x100
vesna_86 [32]

<u>Answer:</u> The solubility of Cd_3(PO_4)_2 in water is 1.18\times 10^{-7}mol/L

<u>Explanation:</u>

The balanced equilibrium reaction for the ionization of cadmium phosphate follows:

Cd_3(PO_4)_2\rightleftharpoons 3Cd^{2+}+2PO_4^{3-}

                      3s       2s

The expression for solubility constant for this reaction will be:

K_{sp}=[Cd^{2+}]^3[PO_4^{3-}]^2

We are given:

K_{sp}=2.5\times 10^{-33}

Putting values in above equation, we get:

2.5\times 10^{-33}=(3s)^3\times (2s)^2\\\\2.5\times 10^{-33}=108s^5\\\\s=1.18\times 10^{-7}mol/L

Hence, the solubility of Cd_3(PO_4)_2 in water is 1.18\times 10^{-7}mol/L

6 0
3 years ago
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