Answer:
A) 
.
B) 
.
C) 0.9 mol.
D) Increasing both temperature and pressure.
Explanation:
Hello,
In this case, given the information, we proceed as follows:
A)
B) For the calculation of Kc, we rate the equilibrium expression:
![Kc=\frac{[NH_3]^2}{[N_2][H_2]^3}](https://tex.z-dn.net/?f=Kc%3D%5Cfrac%7B%5BNH_3%5D%5E2%7D%7B%5BN_2%5D%5BH_2%5D%5E3%7D)
Next, since at equilibrium the concentration of ammonia is 0.6 M (0.9 mol in 1.5 dm³ or L), in terms of the reaction extent 
, we have:
![[NH_3]=0.6M=2*x](https://tex.z-dn.net/?f=%5BNH_3%5D%3D0.6M%3D2%2Ax)
Next, the concentrations of nitrogen and hydrogen at equilibrium are:
![[N_2]=\frac{1.5mol}{1.5L}-x=1M-0.3M=0.7M](https://tex.z-dn.net/?f=%5BN_2%5D%3D%5Cfrac%7B1.5mol%7D%7B1.5L%7D-x%3D1M-0.3M%3D0.7M)
![[H_2]=\frac{4mol}{1.5L}-3*x=2.67M-0.9M=1.77M](https://tex.z-dn.net/?f=%5BH_2%5D%3D%5Cfrac%7B4mol%7D%7B1.5L%7D-3%2Ax%3D2.67M-0.9M%3D1.77M)
Therefore, the equilibrium constant is:
C) In this case, the equilibrium yield of ammonia is clearly 0.9 mol since is the yielded amount once equilibrium is established.
D) Here, since the reaction is endothermic (positive enthalpy change), one way to increase the yield of ammonia is increasing the temperature since heat is reactant for endothermic reactions. Moreover, since this reaction has less moles at the products, another way to increase the yield is increasing the pressure since when pressure is increased the side with fewer moles is favored.
Best regards.
Answer:
Hi
True
Explanation:
Since on the inner and outer surfaces of the membrane, a series of negatively charged amino acids are found, which increase the local concentration of cations. The path of the ions begins on the inner surface filled with water molecules where the ion can retain its hydration sphere. Two thirds of its interior in the membrane the inside of the channel narrows in the region of the selectivity filter, forcing the ion to separate from the water molecules. Oxygen atoms in the selectivity filter replace the water molecules in the K+ hydration sphere, forming a series of coordination spheres through which the ion moves. The preferential stabilization of K+ against Na+ is the basis of the ion selectivity of this filter.
Answer:
a) 10.0 mm
b) 8.7 x 10¹³ times
Explanation:
Atom diameter = 1.06 x 10⁻¹⁰ m ________________ 100%
Nucleus diameter = 2.40 x 10⁻¹⁵ m ______________ x
x = 2.26 x 10⁻³ %
The nucleus diameter is equivalent to 2.26 x 10⁻³ % of the total atom size.
a) The Empire State Building model:
1 ft = 304.8 mm
1454 ft = 443179.2 mm
443179.2 mm______ 100%
y ______ 2.26 x 10⁻³ %
y = 10.0 mm
In this model, the diameter of the nucleus would be 10.0 mm.
b) Sphere volume: V =(4 · π · r³
)/3
V atom = (4 . π .( 0.53x10⁻¹⁰)³ )/3
V atom = 6.2 x 10⁻³¹ m³
V nucleus = (4 . π .( 1.2x10⁻¹⁵)³ )/3
V nucleus = 7.2 x 10⁻⁴⁵ m³
V atom / V nucleus = 6.2 x 10⁻³¹ m³ / 7.2 x 10⁻⁴⁵ m³
V atom / V nucleus = 8.7 x 10¹³
The atom is times 8.7 x 10¹³ larger in volume than its nucleus.
Answer:
it should be 310.18 g/mol :)
Answer:
5.83 g
Explanation:
First, you must start with a balanced equation so you can see the mole ratios.
NaOH + H₃BO₃ --> NaBO₂ + 2H₂O
You can see that it takes 1 mole of sodium hydroxide to form 1 mole of sodium borate. 1:1 ratio
Now you must calculate how many moles of NaOH 35.47 g equals.
Na = 22.99 amu
O = 15.99 amu
H = 1.008 amu
NaOH = 39.997 amu
35.47 g ÷ 39.997 amu = 0.08868 moles of NaOH
Since it's a 1:1 ratio, the same number of moles of NaBO₂ is created. Now you must convert moles to grams.
Na = 22.9 amu
B = 10.81 amu
2 O = 31.998 amu
NaBO₂ = 65.798 amu
0.08868 moles x 65.798 = 5.83 g
